请如何写这个简单的工作选择,在Hibernate查询,或标准休眠加入
SELECT * FROM `call` AS c JOIN `event_customer` AS e ON c.customer_id = e.customer_id WHERE e.dgdelete = FALSE AND c.eventruletype_id = 1 AND e.event_id = 74 AND c.callactivity_id = 3 AND e.calltype = 2
我发现已经有很多建议,但没有任何帮助我呢。
它可能是什么与Hibernate映射?
谢谢。
PS: 这是行不通的
query = session.createQuery("select c from " + Call.class.getSimpleName()+ " as c " + EventCustomer.class.getSimpleName()+ " as e where e.customer_id = c.customer_id and e.event_id = 74");
也是这个工作不
query = session.createQuery("select c from " + Call.class.getSimpleName()+ " as c join " + EventCustomer.class.getSimpleName()+ " as e where e.customer_id = c.customer_id and e.event_id = 74");
而且这个
query = session.createQuery("select c from " + Call.class.getSimpleName()+ " as c join " + EventCustomer.class.getSimpleName()+ " as e on e.customer_id = c.customer_id where e.event_id = 74");
而且这个
query = session.createQuery("select c from " + Call.class.getSimpleName()+ " as c left join " + EventCustomer.class.getSimpleName()+ " as e on e.customer_id = c.customer_id where e.event_id = 74");
,并在某些情况下,我得到这个错误
您以何种方式查询不起作用?会发生什么与你的预期?什么是数据库模式和Java数据模型? – Adrian 2013-05-07 16:08:09