在休眠时加入表的错误

Question

您好，我正在尝试加入User和Candidate表。我想列firstname,lastname,email,phone从Candidate表和加入password列User表。我尝试这样做，但得到某种错误。

CREATE TABLE `candidate` (`candidate_id` bigint(12) NOT NULL,`user_id` int(11) DEFAULT NULL,`firstname` varchar(50) COLLATE utf8_unicode_ci DEFAULT NULL,`lastname` varchar(50) COLLATE utf8_unicode_ci DEFAULT NULL,`dob` date DEFAULT NULL,`gender` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL,`email` varchar(100) COLLATE utf8_unicode_ci NOT NULL,`phone` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL,`address_id` int(11) DEFAULT NULL,`profile_title` varchar(120) COLLATE utf8_unicode_ci DEFAULT NULL,`profile_summary` varchar(10000) COLLATE utf8_unicode_ci DEFAULT NULL,`total_experience` int(11) DEFAULT NULL COMMENT 'year,month',`current_location` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL,`current_salary` double DEFAULT NULL,`expected_salary` double DEFAULT NULL,`status` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL,`percentage` int(45) DEFAULT NULL,`updated_on` timestamp NULL DEFAULT CURRENT_TIMESTAMP,`noticeperiod` int(11) DEFAULT NULL,`martialstatus` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL,`currentoffer` double DEFAULT NULL,`idproof` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL,`industry` varchar(200) COLLATE utf8_unicode_ci DEFAULT NULL,`functionalarea` varchar(200) COLLATE utf8_unicode_ci DEFAULT NULL,`functionalrole` varchar(200) COLLATE utf8_unicode_ci DEFAULT NULL,`resign` bit(1) DEFAULT NULL,`preferlocation` varchar(1000) COLLATE utf8_unicode_ci DEFAULT NULL,`type` varchar(45) COLLATE utf8_unicode_ci DEFAULT NULL,`notice_period_update` timestamp NULL DEFAULT NULL,`passport` bit(1) DEFAULT NULL,`gross_salary` double DEFAULT NULL,`profile_type` varchar(12) COLLATE utf8_unicode_ci DEFAULT NULL,`rrm_user_id` int(11) DEFAULT NULL, PRIMARY KEY (`candidate_id`), KEY `Candidate_Address_idx` (`address_id`),KEY `Can_user` (`user_id`),KEY `CandidateStatus_idx` (`status`),KEY `CandidatePercent_idx` (`percentage`), KEY `user_id_idx` (`rrm_user_id`),CONSTRAINT `Can_user` FOREIGN KEY (`user_id`) REFERENCES `user` (`id`) ON DELETE CASCADE ON UPDATE CASCADE,CONSTRAINT `Candidate_Address` FOREIGN KEY (`address_id`) REFERENCES `address`(`id`) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT `user_id` FOREIGN KEY (`rrm_user_id`) REFERENCES `user` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE=InnoDB DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci; 

我的用户表：

CREATE TABLE `user` (`id` int(11) NOT NULL AUTO_INCREMENT,`username` varchar(255) COLLATE utf8_unicode_ci NOT NULL,`password` varchar(50) COLLATE utf8_unicode_ci DEFAULT NULL,`first_name` varchar(100) COLLATE utf8_unicode_ci DEFAULT NULL,`last_name` varchar(100) COLLATE utf8_unicode_ci DEFAULT NULL,`type` varchar(50) COLLATE utf8_unicode_ci DEFAULT NULL,`active` bit(1) DEFAULT NULL,`deleted` bit(1) DEFAULT NULL,`timezone` varchar(50) COLLATE utf8_unicode_ci DEFAULT NULL,`created_on` timestamp NULL DEFAULT NULL,`updated_on` timestamp NULL DEFAULT CURRENT_TIMESTAMP,`activationcode` varchar(50) COLLATE utf8_unicode_ci DEFAULT NULL,`secure_key` varchar(16) COLLATE utf8_unicode_ci DEFAULT NULL,PRIMARY KEY (`id`),UNIQUE KEY `username_UNIQUE` (`username`)) ENGINE=InnoDB AUTO_INCREMENT=1505 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci; 

我的实体类：

@Table(name = "CANDIDATE")public class SignUp { 
@Id 
@GeneratedValue(strategy = GenerationType.IDENTITY) 
private String candidate_id; 
@Column 
private String firstname; 
@Column 
private String lastname; 
@Column 
private String email; 
@Column 
private String phone; 

public String getCandidate_id() { 
    return candidate_id; 
} 

public void setCandidate_id(String candidate_id) { 
    this.candidate_id = candidate_id; 
} 

public String getFirstname() { 
    return firstname; 
} 

public void setFirstname(String firstname) { 
    this.firstname = firstname; 
} 

public String getLastname() { 
    return lastname; 
} 

public void setLastname(String lastname) { 
    this.lastname = lastname; 
} 

public String getEmail() { 
    return email; 
} 

public void setEmail(String email) { 
    this.email = email; 
} 

public String getPhone() { 
    return phone; 
} 

public void setPhone(String phone) { 
    this.phone = phone; 
} 
@OneToOne(cascade = CascadeType.ALL) 
@JoinColumn(name = "candidate_id") 
private Password password; 

public Password getPassword() { 
    return password; 
} 

public void setPassword(Password password) { 
    this.password = password; 
} 

对于用户表：

@Table(name = "USER")public class Password { @Id 
@GeneratedValue(strategy = GenerationType.IDENTITY) 
private String id; 
@Column 
private String password; 

public String getId() { 
    return id; 
} 

public void setId(String id) { 
    this.id = id; 
} 

public String getPassword() { 
    return password; 
} 

public void setPassword(String password) { 
    this.password = password; 
} 

@OneToOne(cascade = CascadeType.ALL) 
@JoinColumn(name = "user_id") 
private SignUp signUp; 

public SignUp getSignUp() { 
    return signUp; 
} 

public void setSignUp(SignUp signUp) { 
    this.signUp = signUp; 
} 

错误米得到的是低于我的代码中给出：

Hibernate: 
select 
    password0_.id as id1_1_0_, 
    password0_.password as password2_1_0_, 
    password0_.user_id as user_id4_1_0_, 
    signup1_.candidate_id as candidat1_0_1_, 
    signup1_.email as email2_0_1_, 
    signup1_.firstname as firstnam3_0_1_, 
    signup1_.lastname as lastname4_0_1_, 
    signup1_.phone as phone5_0_1_ 
from 
    User password0_ 
left outer join 
    CANDIDATE signup1_ 
     on password0_.user_id=signup1_.candidate_id 
where 
    password0_.id=? 

Jun 01, 2017 4:48:45 PM org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions WARN: SQL Error: 1054, SQLState: 42S22 Jun 01, 2017 4:48:45 PM org.hibernate.engine.jdbc.spi.SqlExceptionHelper logExceptions ERROR: Unknown column 'password0_.user_id' in 'field list'

Answer 1

你映射都很好，你只是错过了user_id在CREATE TABLE user声明基于这种映射：

@OneToOne(cascade = CascadeType.ALL) 
@JoinColumn(name = "user_id") 
private SignUp signUp; 

休眠方愿通过柱联接到CERTIFICATE表。

另外不要忘记在你的DDL中添加外键声明。

Answer 2

尝试使用Jboss反向工程工具进行休眠生成域并避免出现此类错误。它非常容易，您可以在5分钟内从数据库表中创建域。