在java -unexpected输出中将二进制/十进制小数转换为十六进制

Question

我正在尝试编写一个将二进制（有或没有小数部分）输入转换为十六进制的程序，该程序几乎完成，但不幸在十六进制输出中该点（"."）失踪。

假设我的预期产出是e7.6，但我得到的是e76。

只有"."丢失。

这里是我的BinToHex类..

import java.io.*; 

//tried to convert the binary into dec and then dec to hex 
public class BinToHex { 
    double tempDec,fractionpart; 
    long longofintpart,templongDec; 
    String inpu ="11100111.011"; 
    String hexOutput=null,tempDecString,hex = null; 

    static int i = 1; 

    public void convertbintohex() { 

      if (inpu.contains(".")) { 

       int placesAfterPoint = inpu.length() - inpu.indexOf(".") - 1;//every thing 
       long numerator = Long.parseLong(inpu.replace(".", ""), 2);//goes 
       double decimalOfInput = ((double) numerator)/(1L << placesAfterPoint);//alright till here 


       while (true) { 
        tempDec = decimalOfInput * 16; 
        if (tempDec == (int)tempDec) { 
         tempDecString = String.valueOf((long)tempDec); 
         templongDec = Long.parseLong(tempDecString, 10); 
         hexOutput = Long.toHexString(templongDec); 

         break; 
        } else { 
         longofintpart = (long)tempDec; 
         hex=Long.toHexString(longofintpart); 
         if(i==1){ 
          hexOutput = hex + "."; 
          i=i+1; 
         }else{ 
          hexOutput = hexOutput + hex; 
         } 
         fractionpart = tempDec-(int)tempDec; 
         decimalOfInput = fractionpart; 
        } 
       } 
      } else { 
        // this part is ok 
       tempDecString = String.valueOf(Integer.parseInt(inpu, 2)); 
       templongDec = Long.parseLong(tempDecString, 10); 
       hexOutput = Long.toHexString(templongDec); 
      } 
      System.out.println(hexOutput); 
    } 
}  

我的主要测试类..

public class Test{ 
    public static void main(String args[]){ 
     BinToHex i = new BinToHex(); 
     i.convertbintohex();  
    } 
} 

我坚持！ PLZ帮助。

Answer 1

最后找到了适当的算法转换为十进制（有或没有分数）到十六进制。

之外，binary(with or without fraction) to decimal in Java is here

转换十进制（有或没有分数）为十六进制在Java中

import java.math.*; 

public class DecimalToHex{ 
    public String decimalToHex(String decInpString){ 

     StringBuilder hexOut = new StringBuilder(); 
     double doubleOfDecInp = Double.parseDouble(decInpString); 

     if(doubleOfDecInp < 0){ 

      hexOut = hexOut.append("-"); 
      doubleOfDecInp = -doubleOfDecInp; 
     } 

     BigInteger beforedot = new BigDecimal(doubleOfDecInp).toBigInteger(); 
     hexOut.append(beforedot.toString(16)); 

     BigDecimal bfd =new BigDecimal(beforedot); 
     doubleOfDecInp = doubleOfDecInp - bfd.doubleValue(); 

     if(doubleOfDecInp == 0){ 
      return hexOut.toString(); 
     } 
     hexOut.append("."); 

     for (int i = 0; i < 16; ++i) { 
      doubleOfDecInp = doubleOfDecInp * 16; 
      int digit = (int)doubleOfDecInp; 

      hexOut.append(Integer.toHexString(digit)); 

      doubleOfDecInp = doubleOfDecInp - digit; 

      if (doubleOfDecInp == 0) 
       break; 
     } 

     return hexOut.toString(); 
    } 

    public static void main(String args[]){ 

     String decimalInp = "-0.767"; 
     String out ; 
     DecimalToHex i = new DecimalToHex(); 
     out = i.decimalToHex(decimalInp); 
     System.out.println(out);  

    } 
} 

Answer 2

真的，不是我无法抗拒写一个解决方案...有这样长的意见后，JST需要我几分钟^^

final int CODEBASE = 16; 
String input = "11100111.011"; 

//lets see if we have a '.' in our String 
if (input.indexOf(".") > 0) { 

    //yes, we have one - so we can split the string by '.' 
    String splits = input.split("."); 

    //the part left of the dot 
    String beforeDot = splits[0]; 

    //the part right of the dot 
    String afterDot = splits[1]; 

    //it's a incomplete input, we must fill up with 
    //trailing zeros according to out code base 
    afterDot.fillTrailingZeros(afterDot, CODEBASE); 

    //now we can parse the input 
    int asIntBefore = Integer.parseInt(beforeDots, 2); 
    int asIntAfter = Integer.parseInt(afterDot , 2); 

} else { 
    //use your working code for 
    //input wthoput dot HERE 
} 

//fills trailing zeros to input String 
String fillTrailingZeros(String input, int base){ 

    //as long as our String is shorter than the codebase... 
    while (input.length() < base){ 

     //...we have to add trailing zeros 
     input = input +"0"; 
    } 
    return input; 
}