2012-06-29 121 views
5

运行此Linq查询时,我得到一个“NotSupportedException”。 “不支持指定的方法。”什么方法?即使“Count()”被注释掉了,错误也是一样的。空内部例外。NotSupportedException与linq查询和groupBy

堆栈跟踪:

在Hydra.WPF.ViewModels.AddressListViewModel._primaryMemberListWorker_DoWork(对象 发件人,DoWorkEventArgs e)如 M:\项目\水润\ WPF \的ViewModels \ AddressList中\ AddressListViewModel.cs:线 1377在 System.ComponentModel.BackgroundWorker.WorkerThreadStart(对象 参数)

SQL查询:

Select * From _Members 
Inner Join AddressDetailsCCN a on a.MemberId=_Members.MemberID 
Inner Join 
    (
    Select Address+Address2 as CombinedAddress 
    From AddressDetailsCCN Where ListId=84 
    group by Address+Address2 
    Having COUNT(*)>1 
) B on B.CombinedAddress=A.Address+A.Address2 
Where CombinedAddress is not null AND CombinedAddress!='' AND a.ListId=84 
Order by ClientID, CombinedAddress 

的Linq:

var grouped = 
    (from mem in session.Query<Member>() 
    join detail in session.Query<Detail>() on mem.Id equals detail.Member.Id 
    join d2 in (from d3 in session.Query<Detail>() 
       where d3.AddressList.Id == criteria.AddressList.Id 
       group d3 by d3.Address + d3.Address2 into x 
       where x.Count() > 1 
       select x) on detail.Address+detail.Address2 equals d2.Key 
    where detail.AddressList.Id==criteria.AddressList.Id 
    select mem); 
+0

哪条线是1377? – walther

+6

Hibernate的linq实现对基本操作符有问题。我想知道我们什么时候才能最终得到体面的实现...... –

+0

1377只是调用存储此方法的存储库方法。 – Seraph812

回答

0

你如何产生的标准变量?如果这本身就是一个推迟的查询或其他东西,它听起来像是可能的罪魁祸首。如果在查询之前执行var criteriaId = criteria.AddressList.Id;,会发生什么情况,并为您的查询提供criteriaId而不是criteria.AddressList.Id?