t-sql子查询和groupby

Question

在我的query.I选择这种方式所有工作计数全名。

SELECT COUNT(sy.FullName)      [Count Job], 
     sy.FullName        [FullName], 
     MIN(CAST(i.vrp_notificationdate AS DATE)) [Oldest Date] 
FROM BusinessUnit AS b 
     INNER JOIN SystemUser AS sy 
     ON b.BusinessUnitId = sy.BusinessUnitId 
     INNER JOIN Incident AS i 
     ON i.OwnerId = sy.SystemUserId 
GROUP BY f.sy.FullName 

该查询显示该表

--------------------------------- 
Count Job FullName Oldest Date 
    10   a  2011-10-11 
    20   B  2011-10-11 
    55   C  2011-10-11 
--------------------------------- 

，但我想使下表为例子。

-------------------------------------------------------------- 
Count Job FullName Oldest Date  Open Job   Close Job 
    10   A  2011-10-11   5    5 
    20   B  2011-10-11   13    7 
    55   C  2011-10-11   48    7 
------------------------------------------------------------ 

我有我的事件表列名的状态，如果状态码是5个作业是closed.when我使用GROUP BY条件的StatusCode，那么表。而根据我不想秀这显示表。

--------------------------------- 
Count Job FullName Oldest Date 
    10   a  2011-10-11 
    13   B  2011-10-11 
    48   C  2011-10-11 
    7   B  2011-10-11 
    7   C  2011-10-11 
--------------------------------- 

当我在我的T-SQL使用union，我把这个错误“的所有查询使用UNION合并，交叉或EXCEPT运营商必须在其目标列表中的表达式的数目相等。”

如何正确解决这个查询。任何建议。

谢谢。

Answer 1

如何使用CASE和SUM？

SELECT COUNT(sy.FullName)      [Count Job], 
     sy.FullName        [FullName], 
     MIN(CAST(i.vrp_notificationdate AS DATE)) [Oldest Date], 

     SUM(CASE i.status 
      WHEN 5 THEN 1 
      ELSE 0)        [Open Jobs], 

     SUM(CASE i.status 
      WHEN 5 THEN 0 
      ELSE 1)        [Closed Jobs] 

FROM BusinessUnit AS b 
     INNER JOIN SystemUser AS sy 
     ON b.BusinessUnitId = sy.BusinessUnitId 
     INNER JOIN Incident AS i 
     ON i.OwnerId = sy.SystemUserId 
GROUP BY f.sy.FullName