Python的XML解析和默认NS

Question

我正在使用xml.etree.ElementTree来解析XML文件。我想知道是否有一种方法来设置一个默认的ns用于所有的解析操作。

目前我使用的方法类似这样的片段和它的确定：

name_space = 'myns' 
if node.tag == '{%s}Name' % name_space: 

有当ns是对所有标签一样什么更好的办法？

感谢

Answer 1

NS_MAP = {"rdf": "http://www.w3.org/1999/02/22-rdf-syntax-ns#", 
     "rdfs": "http://www.w3.org/2000/01/rdf-schema#", 
     "art": "http://simile.mit.edu/2003/10/ontologies/artstor#", 
     "foaf": "http://xmlns.com/foaf/0.1/", 
     "dcterms": "http://purl.org/dc/terms/", 
     "sioc": "http://rdfs.org/sioc/ns#", 
     "oa": "http://www.openannotation.org/ns/"} 
#short hands the ns 
RDF = "{%s}" % NS_MAP['rdf'] 
RDFS = "{%s}" % NS_MAP['rdfs'] 
ART = "{%s}" % NS_MAP['art'] 
FOAF = "{%s}" % NS_MAP['foaf'] 
DCTERMS = "{%s}" % NS_MAP['dcterms'] 
SIOC = "{%s}" % NS_MAP['sioc'] 
OA = "{%s}" % NS_MAP['oa'] 

，你可以尝试这样的事情