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我想改变下面的bash函数来执行每个命令参数。但是当我运行这个脚本时,第一个echo会按照预期工作,但第二个echo尝试附加到scratch.txt文件并不会真正执行。它只是回显到提示中。bash脚本如何从变量执行命令
#!/bin/sh
clear
function each(){
while read line; do
for cmd in "[email protected]"; do
cmd=${cmd//%/$line}
printf "%s\n" "$cmd"
$cmd
done
done
}
# pipe in the text file and run both commands
# on each line of the file
cat scratch.txt | each 'echo %' 'echo -e "%" >> "scratch.txt"'
exit 0
如何获取$ cmd变量作为命令执行?
我发现从2回答这里的原代码: xargs with multiple commands as argument
使用'eval“$ cmd”' –