使用PHP从JSON响应中访问数组值

Question

我是JSON的新手，我在访问从API调用返回的JSON数组中的特定值时遇到问题。例如，我想访问下面响应数据中的名称值（这些是来自API调用的前两个响应）。我知道我错过了一些明显的东西，但我不能放弃。任何帮助将不胜感激：

ReadResponse::__set_state(array(
    0 => 
    array (
    'address' => '6866 N Rochester Rd', 
    'category' => 'Food & Beverage > Restaurants', 
    'category_ids' => 
    array (
     0 => 347, 
    ), 
    'category_labels' => 
    array (
     0 => 
     array (
     0 => 'Social', 
     1 => 'Food and Dining', 
     2 => 'Restaurants', 
    ), 
    ), 
    'country' => 'us', 
    'factual_id' => '8e6aacfa-b435-407d-83f9-90cec16c1cf8', 
    'latitude' => 42.69804075, 
    'locality' => 'Rochester Hills', 
    'longitude' => -83.134586375, 
    'name' => 'Sushi Little Tokyo', 
    'neighborhood' => 
    array (
     0 => '\\Livernois-Tienken\\', 
    ), 
    'postcode' => '48306', 
    'region' => 'MI', 
    'status' => '1', 
    'tel' => '(248) 608-1260', 
), 
    1 => 
    array (
    'address' => '2964 S Rochester Rd', 
    'category' => 'Food & Beverage > Restaurants', 
    'category_ids' => 
    array (
     0 => 347, 
    ), 
    'category_labels' => 
    array (
     0 => 
     array (
     0 => 'Social', 
     1 => 'Food and Dining', 
     2 => 'Restaurants', 
    ), 
    ), 
    'country' => 'us', 
    'factual_id' => '35d2fc06-a941-4dbf-9dcb-204964fec730', 
    'latitude' => 42.636786765426, 
    'locality' => 'Rochester Hills', 
    'longitude' => -83.131888674506, 
    'name' => 'Pudthi and Sushi', 
    'postcode' => '48307', 
    'region' => 'MI', 
    'status' => '1', 
    'tel' => '(248) 299-6890', 
    'website' => 'http://www.pudthaiandsushi.com', 
), 

Answer 1

试试这个PHP函数json_decode()体现你的JSON响应到一个PHP多维数组，你可以轻松地访问像 数组中值的名称将是

$name = $myPHPArray->country->name; 

Answer 2

这是一个var_export的结果。数据全部包含在ReadResponse的实例中。要了解如何访问数据，请阅读该类的来源或文档。