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我有一个函数来显示包含多个注册ID和数据的JSON数组。我正在使用CodeIgniter。我试图使用通知。从查询中显示有效的JSON数组
public function send_notification($id_user, $message) {
if ($this->muser->cek_follower($id_user) == TRUE) {
$query = $this->muser->get_list_follower($id_user);
$feedback['registration_id'] = array();
foreach ($query->result() as $row) {
$query_list_user = $this->muser->get_all_name_user_from_id($row->id_follower);
if ($query_list_user->num_rows() > 0) {
$row = $query_list_user->row();
$response= $row->regid;
} else {
$feedback = 0;
}
array_push($feedback, $response);
}
$feedback['data'] = $message;
echo json_encode($feedback);
} else {
$feedback = 0;
echo json_encode($feedback);
}
}
我试图摆脱this url,但输出是这样
{
"0": "XX3",
"1": "XX4",
"2": "XX2",
"registration_id": [],
"data": "ada"
}
如何使这样的输出?
{
"registration_id": [
"XX3",
"XX4",
"XX2"
],
"data": "ada"
}
我已经尝试过并尝试过。请帮帮我。谢谢。