加载列表变成具有不同名称的单独变量

Question

Debian testing，bash ...

我试图从现有程序加载变量。

设置程序变量

xPROGS="$(echo -e "exiftool\nrsync\nxsel")" 

试图创建与X（项目名称）

echo "$xPROGS" | while read z; do x$z="$(whereis -b "$z" | awk '{print $2}')" ; done 

错误变量;

bash: xexiftool=/usr/bin/rsync: No such file or directory 
bash: xrsync=/usr/bin/rsync: No such file or directory 
bash: xxsel=/usr/bin/rsync: No such file or directory 

This works;

$ whereis -b rsync | awk '{print $2}' 

我无法实现成功更改变量名称。

有人可以请帮忙。

Answer 1

$ cat t.sh 
#!/bin/bash 

progs=(exiftool rsync xsel) 

for prog in "${progs[@]}"; do 
     read -r _ "x${prog}" _ <<< "$(whereis -b "${prog}")" 
done 

echo "exiftool: [${xexiftool}]" 
echo "rsync: [${xrsync}]" 
echo "xsel:  [${xxsel}]" 

rsync命令将不会改变其位置

$ ./t.sh 
exiftool: [] 
rsync: [/usr/bin/rsync] 
xsel:  [] 

Answer 2

@Etan赖斯纳提供从那里以下代码基于链接：

echo "$xPROGS" | while read z; do IFS= read -r "x$z" <<<$(whereis -b rsync | awk '{print $2}') ; done 

但我觉得，在文件系统树

RSYNC=$(whereis -b rsync); RSYNC="${RSYNC#* }"; echo "$xPROGS" | while read z; do IFS= read -r "x$z" <<<"$RSYNC" ; done