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我使用下面的代码在两个UIImageView之间转换。2 UIImages之间的转换
-(void)performTransitionNew: (NSInteger)type subType:(NSInteger)subType
fromImageView:(UIImageView *)fromImageView
toImageView:(UIImageView *)toImageView duration:(NSInteger)duration;
{
CATransition *transition = [CATransition animation];
transition.duration = duration;//0.3;
transition.timingFunction = [CAMediaTimingFunction functionWithName:kCAMediaTimingFunctionEaseInEaseOut];
NSString *types[4] = {kCATransitionMoveIn, kCATransitionPush, kCATransitionReveal, kCATransitionFade};
NSString *subtypes[4] = { kCATransitionFromLeft, kCATransitionFromRight, kCATransitionFromTop, kCATransitionFromBottom};
transition.type = types[type];
transition.subtype = subtypes[subType];
transitioning = YES;
transition.delegate = self;
[self.aUIView.layer addAnimation:transition forKey:nil];
fromImageView.hidden = YES;
toImageView.hidden = NO;
UIImageView *tmp = toImageView;
toImageView = fromImageView;
toImageView = tmp;
}
它们都在UIView'aUIView'上。 我想要的结果是这样的:
,但它显示是这样的:
它看起来像toImageView来自aUIView之外。
欢迎任何评论。
甚至我用[self.view bringSubviewToFront:anyUIViewAroundaUIView]; – arachide 2010-10-21 11:59:57
将任何uiview带到前面,结果一样。它会透明地显示到UIImageView – arachide 2010-10-21 12:00:48
和toImageView肯定是一个UIView的子视图,对吧? – Maffo 2010-10-21 13:20:45