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我一直在使用这个简单的程序试图解决这个错误的方式太长。我正在使用Arduino,我只是想制作一个简单的温度监视器来打开和关闭一些开关。我一直收到错误“功能定义在此之前不允许'{'标记。”如果有人比我知道的更多,并且能够帮助我,那会很棒!函数定义在这里是不允许的'{'token
float temp;
void setup(){
pinMode(13, OUTPUT);
pinMode(8, OUTPUT);
pinMode(9, OUTPUT);
pinMode(10, OUTPUT);
pinMode(11, OUTPUT);
pinMode(7, INPUT);
pinMode(0, INPUT);
Serial.begin(9600);
}
void highHeat(){
temp = analogRead(0);
temp = (5.0*temp*100.0/1024.0);
if (temp > 79)
{
digitalWrite(8, LOW);
digitalWrite(9, LOW);
digitalWrite(10, LOW);
digitalWrite(11, LOW);
digitalWrite(13, LOW);
}
if (temp < 78)
{
digitalWrite(8, HIGH);
digitalWrite(9, HIGH);
digitalWrite(10, HIGH);
digitalWrite(11, HIGH);
digitalWrite(13, HIGH);
}
delay(10000);
}
void lowHeat(){
temp = analogRead(0);
temp = (5.0*temp*100.0/1024.0);
if (temp > 26)
{
digitalWrite(8, LOW);
digitalWrite(9, LOW);
digitalWrite(10, LOW);
digitalWrite(11, LOW);
digitalWrite(13, LOW);
}
if (temp < 25)
{
digitalWrite(8, HIGH);
digitalWrite(9, HIGH);
digitalWrite(10, HIGH);
digitalWrite(11, HIGH);
digitalWrite(13, HIGH);
}
delay(10000);
}
void loop(){
if (6 == HIGH)
{
delay(2000);
if (6 == HIGH)
{
digitalWrite(13, HIGH);
delay(500);
digitalWrite(13, LOW);
delay(500);
digitalWrite(13, HIGH);
delay(500);
digitalWrite(13, LOW);
delay(500);
digitalWrite(13, HIGH);
delay(500);
digitalWrite(13, LOW);
delay(500);
digitalWrite(13, HIGH);
delay(500);
digitalWrite(13, LOW);
void loop(){
lowHeat();
}
}
if (6 == LOW)
{
digitalWrite(13, HIGH);
delay(500);
digitalWrite(13, LOW);
delay(500);
digitalWrite(13, HIGH);
delay(500);
digitalWrite(13, LOW);
void loop(){
highHeat();
}
}
}
}
P.S.我做了一些搜索,发现很多帖子都是相同的标题,但他们似乎从来没有与我的问题有关,所以我只是想我会寻求一些帮助。
是的,你可能想要一个'while'循环来代替。 – Huey
谢谢,当我回家时我会尝试。 – user2532869