2014-06-28 45 views
-1

我正在尝试生成某个国家给定城市内天主教徒百分比的估计值,并使用多级回归和调查数据后分层。Tapply仅产生缺失值

该方法适合多级Logit并生成因变量的预测概率。然后使用样本的事后分级对人口普查数据加权概率。

我可以生成初始估计值(基本上就是调查数据中给定个体的天主教徒的预测概率)。但是,当我尝试使用下面最后一行代码取平均值时,它只返回不适用于每个城市。最初的细胞预测有一些缺失的值,但远不及大多数。

我不明白为什么我不能生成市政加权平均数,因为我遵循使用不同数据的程序。任何帮助将不胜感激。

rm(list=ls(all=TRUE)) 

library("arm") 
library("foreign") 

#read in megapoll and attach 
ES.data <- read.dta("ES4.dta", convert.underscore = TRUE) 

#read in municipal-level dataset 

munilevel <- read.dta("election.dta",convert.underscore = TRUE) 
munilevel <- munilevel[order(munilevel$municode),] 

#read in Census data 
Census <- read.dta("poststratification4.dta",convert.underscore = TRUE) 
Census <- Census[order(Census$municode),] 
Census$municode <- match(Census$municode, munilevel$municode) 

#Create index variables 

#At level of megapoll 

ES.data$ur.female <- (ES.data$female *2) + ES.data$ur 
ES.data$age.edr <- 6 * (ES.data$age -1) + ES.data$edr 

#At census level (same coding as above for all variables) 
Census$cur.cfemale <- (Census$cfemale *2) + Census$cur 
Census$cage.cedr <- 6 * (Census$cage -1) + Census$cedr 

##Municipal level variables 
Census$c.arena<- munilevel$c.arena[Census$municode] 
Census$c.fmln <- munilevel$c.fmln[Census$municode] 



#run individual-level opinion model 

individual.model1 <- glmer(formula = catholic ~ (1|ur.female) + (1|age) 
+ (1|edr) + (1|age.edr) + (1|municode) + p.arena +p.fmln 
,data=ES.data, family=binomial(link="logit")) 
display(individual.model1) 



#examine random effects and standard errors for urban-female 
ranef(individual.model1)$ur.female 
se.ranef(individual.model1)$ur.female 

#create vector of state ranefs and then fill in missing ones 
muni.ranefs <- array(NA,c(66,1)) 
dimnames(muni.ranefs) <- list(c(munilevel$municode),"effect") 
for(i in munilevel$municode){ 
muni.ranefs[i,1] <- ranef(individual.model1)$municode[i,1] 
} 
muni.ranefs[,1][is.na(muni.ranefs[,1])] <- 0 #set states with missing REs (b/c not in  data) to zero 


#create a prediction for each cell in Census data 
cellpred1 <- invlogit(fixef(individual.model1)["(Intercept)"] 
    +ranef(individual.model1)$ur.female[Census$cur.cfemale,1] 
    +ranef(individual.model1)$age[Census$cage,1] 
    +ranef(individual.model1)$edr[Census$cedr,1] 
    +ranef(individual.model1)$age.edr[Census$cage.cedr,1] 
    +muni.ranefs[Census$municode,1] 
    +(fixef(individual.model1)["p.fmln"] *Census$c.fmln) # municipal level 
    +(fixef(individual.model1)["p.arena"] *Census$c.arena)) # municipal level 



#weights the prediction by the freq of cell          
cellpredweighted1 <- cellpred1 * Census$cpercent.muni 

#calculates the percent within each municipality (weighted average of responses) 
munipred <- 100* as.vector(tapply(cellpredweighted1, Census$municode, sum)) 
munipred 

回答

1

大量的代码是完全没有数据的冗余!我想你在对象cellpredweighted1中有NA s,默认情况下sum()NAs传播给答案,因为如果一个向量的一个或多个元素是NA那么根据定义,那些元素的总和也是NA

如果上面是这里的情况,那么简单地将na.rm = TRUE添加到tapply()调用应该可以解决问题。

tapply(cellpredweighted1, Census$municode, sum, na.rm = TRUE) 

你应该问自己,为什么在这个阶段,如果从早期的过程中的错误,这些结果是NA秒。