如何使从蟒蛇

-2

我试图让在python使用curl POST请求，但下面的脚本卷曲POST请求抛出错误如何使从蟒蛇

import os 

first_name1 = "raj" 
last_name1 = "kiran" 
full_name = "raj kiran" 
headline = "astd" 
location1 = "USA" 
current_company1 = "ss" 

curl_req = 'curl -X POST -H "Content-Type: application/json" -d '{"first_name":"{0}","last_name":"{1}","current_company":"{2}","title":"{3}","campus":"","location":"{4}","display_name":"{5}","find_personal_email":"true"}' http://localhost:8090'.format(first_name1,last_name1,current_company1,headline,location1,full_name) 

os.popen(curl_req)

错误：

SyntaxError: invalid syntax

如何使上述程序工作？

来源

2016-06-14 Mounarajan

你为什么要这样做，当你可以使用'request'？ –

如何使用请求以上述格式向此http：// localhost：8090发送发布请求？ – Mounarajan

阅读http://docs.python-requests.org/en/latest/ – 2016-06-14 10:21:12

代码中的问题是引号。将其更改为：

curl_req = '''curl -X POST -H "Content-Type: application/json" -d '{"first_name":"{0}","last_name":"{1}","current_company":"{2}","title":"{3}","campus":"","location":"{4}","display_name":"{5}","find_personal_email":"true"}' http://localhost:8090'''.format(first_name1,last_name1,current_company1,headline,location1,full_name)

但是，正如在评论中提到的，requests将永远是一个更好的选择。

请求语法：我已经用了卷曲请求转换为Python的请求

import requests 
post_data = { 
    # all the data you want to send 
} 
response = requests.post('http://localhost:8090', data=post_data) 
print response.text

来源

2016-06-14 10:21:32

你能帮我使用请求吗？ – Mounarajan

一个很好的资源是curlconverter。您可以输入您的cURL请求，并将其格式化为Python requests。

作为一个方面说明，它也可以转换为PHP和Node.js.

希望有帮助！

来源

2017-09-25 19:53:21 cheevahagadog

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