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我写了一个简单的卡处理程序的代码,你可以输入正在玩的玩家的数量,它会为他们每个加5(河流,翻牌等等)输出两张卡片让m不能等于1?
我是想知道如何让m不能等于1,这样如果用户输入一个就会显示错误。
另外,我想知道是否有任何方式,以便它更具有视觉吸引力分隔每个球员卡和5张牌,并给他们的标题骗“玩家1”,“翻牌” ......
谢谢!
public static void main(String[] args) throws IOException {
BufferedReader in;
int x;
String playerx;
in = new BufferedReader(new InputStreamReader(System.in));
System.out.println("How many players are playing?");
playerx = in.readLine(); //user input for menu selection
x = Integer.valueOf(playerx).intValue();
// create a deck of 52 cards and suit and rank sets
String[] suit = { "Clubs", "Diamonds", "Hearts", "Spades" };
String[] rank = { "2", "3", "4", "5", "6", "7", "8", "9", "10",
"Jack", "Queen", "King", "Ace" };
//initialize variables
int suits = suit.length;
int ranks = rank.length;
int n = suits * ranks;
//counter (5 house cards and 2 cards per player entered)
int m = 5+(x*2);
// initialize deck
String[] deck = new String[n];
for (int i = 0; i < ranks; i++) {
for (int j = 0; j < suits; j++) {
deck[suits*i + j] = rank[i] + " of " + suit[j];
}
}
// create random 5 cards
for (int i = 0; i < m; i++) {
int r = i + (int) (Math.random() * (n-i));
String t = deck[r];
deck[r] = deck[i];
deck[i] = t;
}
// print results
for (int i = 0; i < m; i++){
System.out.println(deck[i]);
}
}
}
检查,如果是1,如果它是抛出一个错误? –
据我所见,'m == 1' IFF'x == - 2'('m = 5+(x * 2)'),但x是代表'playerX'的“int”那?) – avrahamcool