的最小函数值我有一个表与餐馆连锁店的GPS位置,并想返回最近的餐馆的地址,以点(A)一定半径SQLite的选择分组结果
SELECT *
, MIN(distance($lat, $lon, lat, lon)) as miles
FROM all_restaurants
WHERE lat between $lat1 and $lat2
AND lon between $lon1 and $lon2
AND miles < $miles
GROUP BY restaurant_id
ORDER BY miles ASC
, company_name ASC
LIMIT 500
回报误差范围内
误用骨料的:)MIN(