下面的代码可能会产生未定义的行为吗?std :: thread未定义的行为
unsigned int total_threads = 10;
vector<thread> t(total_threads);
unsigned int *nums = (unsigned int*)calloc(total_threads, sizeof(int));
for(unsigned int i = 0; i < 1000; i++)
{
for(unsigned int j = 0; j < total_threads; j++)
t[j] = thread(func_, std::ref(nums[j]));
for(unsigned int j = 0; j < total_threads; j++)
t[j].join();
for(unsigned int j = 0; j < total_threads; j++)
{
cout << nums[j] << " ";
nums[j] = 0;
}
}
它取决于'func_'的功能。只要它修改了它给予的参考价值,我相当肯定这是完全明确的。 –