更改函数中的变量

Question

from random import randint 

count = 0 
Validation = False 

def generateNumber(): 
    Number = randint(1, 10) 
    return Number 

def checkNumber(Guess): 
    Number = generateNumber() 
    if int(Guess) == Number and count < 1: 
     return "First time right! Genius?" 
     Validation = True 

    elif int(Guess) == Number and count == 2: 
     return "Correct. Second time, nice!" 
     Validation = True 
    elif int(Guess) == Number and count < 4: 
     return "Correct. Good job." 
     Validation = True 
    elif int(Guess) == Number and count > 3: 
     return "Correct. Took you long enough." 
     Validation = True 
    else: 
     return "Wrong! Try again " 

while Validation == False: 
    Guess = input("Please guess a number between 1 to 10: ") 
    print (checkNumber(Guess)) 
    count += 1 
else: 
    TryAgain = input("Would you like to try again? y/n \n") 

所以问题是，当用户猜测正确的数字。验证应该转为True。所以while循环将停止循环。但是当玩家猜测到正确的数字时，变量验证不会变为真。

Answer 1

Python中的全局变量有点棘手，仅仅在文件顶部声明一个变量是不够的。

另外，请您设置的验证值，然后返回的值，导致功能设置这个变量

末发行前终止是同时逻辑，见校正使用输入和其他压痕

的的raw_input而不是

只读访问全局变量按预期工作，但在函数中更改其值时需要一个额外的步骤，则应该将全局变量声明为全局变量。你的情况：

def generateNumber(): 
    Number = randint(1, 10) 
    return Number 

def checkNumber(Guess): 
    global Validation #<-- this instructs Python to use the global variable 
    Number = generateNumber() 
    if int(Guess) == Number and count < 1: 
     Validation = True 
     return "First time right! Genius?" 

    elif int(Guess) == Number and count == 2: 
     Validation = True 
     return "Correct. Second time, nice!" 

    elif int(Guess) == Number and count < 4: 
     Validation = True 
     return "Correct. Good job." 

    elif int(Guess) == Number and count > 3: 
     Validation = True 
     return "Correct. Took you long enough." 

    else: 
     return "Wrong! Try again " 

while Validation == False: 
    Guess = input("Please guess a number between 1 to 10: ") 
    print (checkNumber(Guess)) 
    count += 1 
    if (Validation): 
     if (raw_input("Would you like to try again? y/n \n") == "y"): 
      count = 0 
      Validation = False 
     else: 
      break 

Answer 2

您需要设置验证到真之前，你从方法返回，就像这样：

if int(Guess) == Number and count < 1: 
    Validation = True 
    return "First time right! Genius?" 

这样做对所有if语句。

Answer 3

我发现两（半）的问题在你的代码：

1. 正如Ishay佩莱德指出的那样，你需要之前进行确认全球
2. 你的“回归”的语句位于你更改“验证”
3. 的价值“而”没有“其他”

下面是更新后的代码：

from random import randint 

count = 0 
Validation = False 

def generateNumber(): 
    Number = randint(1, 10) 
    return Number 

def checkNumber(Guess): 
    global Validation 
    Number = generateNumber() 
    if int(Guess) == Number and count < 1: 
     Validation = True 
     return "First time right! Genius?" 

    elif int(Guess) == Number and count == 2: 
     Validation = True 
     return "Correct. Second time, nice!" 
    elif int(Guess) == Number and count < 4: 
     Validation = True 
     return "Correct. Good job." 
    elif int(Guess) == Number and count > 3: 
     Validation = True 
     return "Correct. Took you long enough." 
    else: 
     return "Wrong! Try again " 


while Validation == False: 
    Guess = input("Please guess a number between 1 to 10: ") 
    print (checkNumber(Guess)) 
    print "validation: %s" % str(Validation) 
    count += 1 

TryAgain = input("Would you like to try again? y/n \n") 

Answer 4

除了全局变量问题，您还需要制作另一组修复程序。 “返回”语句之后，所有赋值为Validation = True。 Validation = True永远不会执行！它将在执行之前退出该功能。在“返回”之前设置“Validation = True”。你仍然需要像Ishay所说的那样拥有全球声明。