我一直在试图让我的C++程序检查数组中的重复项,因为我需要这个程序来编写程序。但是,它不起作用,我想我知道这个问题是怎么回事,但我不知道如何解决它。如何确保数组中没有重复项?
#include <iostream>
#include <cstdlib>
#include <ctime>
#include <algorithm>
using namespace std;
int asknum(int ask);
int check(int checking);
bool error = false;
int test [10] = {};
int i = 0;
int gen = 0;
int main() {
//int gen = 0;
for (i=0; i<10; i++) {
gen = asknum(gen);
}
for (int b=0; b<10; b++) {
cout << test [b] << endl;
}
return 0;
}
int asknum(int ask) {
ask = 0;
gen = 0;
int nouse;
cout << "Please enter a value: ";
cin >> ask;
error = 0;
nouse = check(ask);
}
int check(int checking) {
int n = 0;
for (n=0; n<10; n++) {
int temp = test [n];
if (temp == checking) {
cout << "Value is the same. Enter another value.\n";
error = 1;
gen = asknum(gen);
}
}
if (n == 10) {
if (error == 0) {
gen = 0;
test [i] = checking;
}
}
}
我的代码有什么问题?我第一次编写代码时,它的工作很完美。但是当我注意到一个缺陷,那就是如果你经常输入一个现在的数字,它会停止询问一个新的数字,我决定把代码移入函数,但现在它不能正常工作!这里是输出:
Please enter a number: 1
Please enter a number: 2
Please enter a number: 3
Please enter a number: 3
That number already is used. Please type in another value.
Please enter a number: 4
Please enter a number: 5
Please enter a number: 6
Please enter a number: 7
Please enter a number: 8
Please enter a number: 9
Please enter a number: 10
1
2
3
3
5
6
7
8
9
10
我认为通信有问题。请帮忙!
谢谢!
使用'std :: set'来保证容器不会包含重复项。 – user0042
我会在哪里放置? –
而不是'int test [10] = {};':'std :: set test;'你的代码需要更多的适配。 –
user0042