选择由计数，但不计

Question

表是这样排序的列，说这表示在日志文件中各类事件的

<type> <date> 

我想选择前5个最常见的类型

select type,count(type) as c from log order by c desc limit 5 

这工作正常，但我只想要类型列，所以我可以使用这是一个where in子查询。我怎么做？我不能工作，如何剿计数科拉姆

Answer 1

很简单：

SELECT type FROM log GROUP BY type ORDER BY COUNT(type) DESC LIMIT 5 

Answer 2

就使这个子查询过：

SELECT TYPE 
FROM LOG 
WHERE TYPE IN 
    (select type,count(type) as c 
    from log 
    order by c desc limit 5) 

Answer 3

不使用SQLite的，但我会写这样的事情在SQL服务器中;也许有一些想法可以偷走？

select top (5) type from log group by type order by count(type) desc 

Answer 4

您没有指定RDBMS，这很大程度上取决于您使用的是哪一个。这里有一些选项。

-- works in postgres and mysql 
select type from log group by type order by count(*) desc limit 5; 

-- this variant works in mssql but probably no where else (maybe sybase) 
select top(5) type from log group by type order by count(*) desc; 

-- works in posgres and mssqlserver but not mysql or oracle 
select 
     type 
    from (select 
     type, 
     row_number() over (order by count(*) desc) as r 
    from 
     log 
    group by 
     type 
) as t 
    where 
    r <= 5 
; 

-- portable to all standards compliant RDMS 
select 
     type 
    from (select 
     type, 
     row_number() over (order by c) as r 
    from 
     (select 
       type, 
       count(*) as c 
      from 
       log 
      group by 
       type 
     ) as t 
) as t 
    where 
    r <= 5 
; 

-- works if you don't have windowing functions, but returns more than 5 rows 
select 
     type 
    from 
     (select 
       type, 
       count(*) as c 
      from 
       log 
      group by 
       type 
     ) as t 
    order by 
     c desc 
;