2015-09-18 140 views
3

我用这个异常处理程序来处理我的春节,启动应用程序(REST API)一些特定的例外:如何处理@ControllerAdvice中所有未处理的异常?

@ControllerAdvice 
class GlobalExceptionHandler { 

    @ExceptionHandler(NotFoundException.class) 
    @ResponseStatus(HttpStatus.NOT_FOUND) 
    public 
    @ResponseBody 
    ResponseMessage notFound(NotFoundException ex) { 
     return new NotFoundResponseMessage(ex.getMessage()); 
    } 

    @ResponseStatus(value = HttpStatus.UNSUPPORTED_MEDIA_TYPE) 
    @ExceptionHandler(HttpMediaTypeNotSupportedException.class) 
    public 
    @ResponseBody 
    ResponseMessage unsupportedMediaType(HttpMediaTypeNotSupportedException ex) { 
     return new UnsupportedMediaTypeResponseMessage(ex.getMessage()); 
    } 

    @ExceptionHandler(UnauthorizedException.class) 
    @ResponseStatus(HttpStatus.UNAUTHORIZED) 
    public 
    @ResponseBody 
    ResponseMessage unauthorized(UnauthorizedException ex) { 
     return new UnauthorizedResponseMessage(ex.getMessage()); 
    } 

    @ExceptionHandler(HttpRequestMethodNotSupportedException.class) 
    @ResponseStatus(HttpStatus.METHOD_NOT_ALLOWED) 
    public 
    @ResponseBody 
    ResponseMessage methodNotAllowed(HttpRequestMethodNotSupportedException ex) { 
     return new MethodNotAllowedResponseMessage(ex.getMessage()); 
    } 

    @ExceptionHandler(ForbiddenException.class) 
    @ResponseStatus(HttpStatus.FORBIDDEN) 
    public 
    @ResponseBody 
    ResponseMessage forbidden(ForbiddenException ex) { 
     return new ForbiddenResponseMessage(ex.getMessage()); 
    } 

} 

,我想处理所有其他异常与一个“全球性”的处理方法。但是,我需要得到HTTP状态代码在这种方法来处理错误信息等

问题

有一些方法如何将所有非处理的异常重定向到一个特定的方法是什么?我该怎么做?

+1

添加处理'Exception'的方法。最具体的将被选择用于错误处理......并且简单地添加'HttpServletRequest'和/或'HttpServletResponse'作为方法参数。 –

回答

1

docs

在实现HandlerExceptionResolver将用于 拦截和处理在MVC系统引发的任何异常,而不是 由控制器进行处理DispatcherServlet会的申请 上下文中声明任何Spring bean的。

public interface HandlerExceptionResolver { 
    ModelAndView resolveException(HttpServletRequest request, HttpServletResponse response, Object handler, Exception ex); 
} 
+0

我读过这篇文章,但我不需要'ModelAndView',应该通过'@ ResponseBody'返回我的'ResponseMessage'。 – Artegon