相等的节点应置于单个计数器元素下。 输入:节点上的XSLT 1.0逻辑
<Move-Afile>
<Afile>
<Item>
<PACK050>
<PackNumber>1234</PackNumber>
</PACK050>
</Item>
<Item>
<PACK050>
<PackNumber>567</PackNumber>
</PACK050>
</Item>
<Item>
<PACK050>
<PackNumber>567</PackNumber>
</PACK050>
</Item>
<Item>
<PACK050>
<PackNumber>126</PackNumber>
</PACK050>
</Item>
<Item>
<PACK050>
<PackNumber>567</PackNumber>
</PACK050>
</Item>
</Afile>
</Move-Afile>
因为我们需要增加计数器变量中的每个包号,但这里有一个条件是存在一样,如果以前是等于当前我们必须忽略计数器(有没有需要增加)像下面的output.all相等的节点下一个计数器下面的输出。
XSLT模板应该包含如下结构的<for-each>
。
<xsl:template match="/">
<A>
<target>
<xsl:for-each select="/Move-Afile/Afile/Item/PACK050/PackNumber">
<xsl:variable name="count">
<!-- get the count here-->
</xsl:variable>
<counter>$count</counter>
<PNumber><xsl:value-of select="."/></PNumber>
</xsl:for-each>
</target>
</A>
</xsl:template>
输出:
<A>
<target>
<Item>
<PACK050>
<counter>1</counter><!-- if previous <PackNumber> is not equal to current <PackNumber> increment the count-->
<PNumber>1234</PNumber>
</PACK050>
</Item>
<Item
<PACK050>
<counter>2</counter><!-- if previous <PackNumber> is not equal to current <PackNumber> increment the count-->
<PNumber>567</PNumber>
</PACK050>
</Item>
<Item><!-- if previous <PackNumber> is equal to current <PackNumber> ignore the counter -->
<PACK050>
<PNumber>567</PNumber>
</PACK050>
</Item>
<Item><!-- if previous <PackNumber> is equal to current <PackNumber> ignore the counter -->
<PACK050>
<PNumber>567</PNumber>
</PACK050>
</Item>
<Item>
<PACK050>
<counter>3</counter><!-- if previous <PackNumber> is not equal to current <PackNumber> increment the count-->
<PNumber>126</PNumber>
</PACK050>
</Item>
</target>
</A>
+1我的回答有些sl;,你的更完整。 – ABach