我有哪里是内部的一些部件模块XML ....XSLT 1.0组和计数节点
<?xml version="1.0"?>
<root>
<modul id="1">
<part id="01" part_number="AAA"/>
<part id="02" part_number="AAA"/>
<part id="03" part_number="AAA"/>
<part id="04" part_number="BBB"/>
</modul>
<modul id="2">
<part id="05" part_number="AAA"/>
<part id="06" part_number="AAA"/>
<part id="07" part_number="CCC"/>
<part id="08" part_number="BBB"/>
</modul>
</root>
欲组由每个模件内部PART_NUMBER和计数节点occurancies:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:key name="keyPartNumber" match="part" use="@part_number"/>
<xsl:template match="/">
<xsl:for-each select="root/modul">
<modul name="{@id}">
<xsl:for-each select="part[generate-id() = generate-id(key('keyPartNumber',@part_number)[1])]">
<xsl:sort select="@part_number" order="ascending" data-type="text"/>
<node title="{@part_number} (quantity: {count(key('keyPartNumber',@part_number))})" />
</xsl:for-each>
</modul>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
但结果是我得到的是不是我想要的:
<?xml version="1.0" encoding="UTF-8"?>
<modul name="1">
<node title="AAA (quantity: 5)"/>
<node title="BBB (quantity: 2)"/>
</modul>
<modul name="2">
<node title="CCC (quantity: 1)"/>
</modul>
的例外结果将是:
<?xml version="1.0" encoding="UTF-8"?>
<modul name="1">
<node title="AAA (quantity: 3)"/>
<node title="BBB (quantity: 1)"/>
</modul>
<modul name="2">
<node title="AAA (quantity: 2)"/>
<node title="BBB (quantity: 1)"/>
<node title="CCC (quantity: 1)"/>
</modul>
我该如何认识到这一点?是否有可能为每个模块动态创建密钥?