如何写事件的钩子蝗虫对个人的响应时间要求

Question

我打算用蝗虫来测试性能我的网络服务器， 与下面的代码的问题是，它只是给我的平均时间

我的基本代码如下

from locust import HttpLocust, TaskSet, task, events, web 
def index(l): 
     l.client.get("/") 

def stats(l): 
     l.client.get("/stats/requests") 

class MyTaskSet(TaskSet): 
     tasks = [index,stats] 

class MyLocust(HttpLocust): 
    host = "http://127.0.0.1:8089" 
    min_wait = 2000 
    max_wait = 5000 
    task_set = MyTaskSet 
    request_success_stats = [list()] 
    request_fail_stats = [list()] 

    def __init__(self): 
     super(MyLocust, self).__init__() 
     locust.events.request_success += self.hook_request_success 
     locust.events.request_failure += self.hook_request_fail 
     locust.events.quitting += self.hook_locust_quit 

    def hook_request_success(self, request_type, name, response_time, response_length): 
      self.request_success_stats.append([name, request_type, response_time, response_length]) 

    def hook_request_fail(self, request_type, name, response_time, exception): 
     self.request_fail_stats.append([name, request_type, response_time, exception]) 

    def hook_locust_quit(self): 
     self.save_success_stats() 

    def save_success_stats(self): 
     import csv 
     with open('success_req_stats.csv', 'wb') as csv_file: 
      writer = csv.writer(csv_file) 
       for value in self.request_success_stats: 
        writer.writerow(value) 

Answer 1

这是测量实际的响应时间。

这里美中不足的是，如果有效载荷具有多个URI的则响应时间为每个将被记录，其具有同时记录的结果被依次排序/除去重复