bash：Python中出现意外令牌`newline'附近的语法错误号码游戏

Question

我试图在Python中创建一个简单的“猜数字游戏”。

我的代码：

minimum = 1 
maximum = 100 
current_number = 50 




def new_number(x): 
    global sign, current_number, minimum, maximum 
    if x == ">": 
     minimum = current_number + 1 
     curent_number = minimum + maximum/2 
     guess() 
    else: 
     maximum = current_number - 1 
     current_number = minimum + maximum/2 
     guess() 


print "Pick a number between 1 - 100, keep it in your head" 
print "I'm going to guess it within 6 guesses" 

def guess(): 
    print "Is your number > or < %d" % current_number 

guess() 

sign = raw_input(": ") 
new_number(sign) 

试图以数字“27”来运行它，似乎对于第一次迭代做工精细。然而，输入被放置在第二次迭代中，其中输入==“>”，收到后：

bash: syntax error near unexpected token `newline' 

有该错误指向没有具体的行号。我确定它与if x == ">":部分有关。

Answer 1

你不在循环中，你的'第二次迭代'根本不是python，你的python脚本已经返回。

检查这些改变你的代码：

minimum = 1 
maximum = 100 
current_number = 50 




def new_number(x): 
    global sign, current_number, minimum, maximum 
    if x == ">": 
     minimum = current_number + 1 
     current_number = (minimum + maximum)/2 
     guess() 
    else: 
     maximum = current_number - 1 
     current_number = (minimum + maximum)/2 
     guess() 


print "Pick a number between 1 - 100, keep it in your head" 
print "I'm going to guess it within 6 guesses" 

def guess(): 
    print "Is your number >, < or = %d" % current_number 

guess() 

while(1): 
    sign = raw_input(": ") 
    if (sign == '='): 
     break 
    new_number(sign) 

的问题是，当你在一个循环中没有，当你的脚本第一次迭代之后返回，你可能在bash打< <enter>，让你有一个bash错误。

我还建议你重构你的代码以避免使用全局变量，看看：Why are global variables evil?看看这对你的代码有什么坏处。