自我加入mysql复杂查询

Question

我有一个名为call_charges的表，里面有以下数据。

我需要获得所有未付款的付款，其付款重试也未付。

具有transaction_bid非空和is_paid 0，将返回记录与id 6和10 但是id 6即行有具有支付重试（id 12，与retry_id 6和is_paid 1），所以用id 6行不应该在结果中出现。

我曾尝试用：

SELECT `call_charges`.* FROM `call_charges` LEFT JOIN `call_charges` AS 
`retries_call_charges` ON `retries_call_charges`.`retry_id` = `call_charges`.`id` 
WHERE `call_charges`.`is_paid` = 0 AND (`call_charges`.`transaction_bid` IS NOT NULL 
AND `call_charges`.`retry_id` IS NULL) 

但它与id 6和10

感谢提前返回两排。

Answer 1

在这里你去：

SELECT c1.id 
FROM call_charges c1 
LEFT JOIN call_charges c2 
ON c1.id = c2.retry_id AND c2.is_paid = 1 
WHERE c1.transaction_bid IS NOT NULL 
AND c1.is_paid = 0 
AND c2.id IS NULL 
AND c1.retry_id IS NULL 

工作小提琴：因为LEFT JOIN已使用http://sqlfiddle.com/#!2/29549/13

c2.id可能为空。当c1.id与c2.retry_id不匹配时，则c2.id将为NULL。