我从ColdFusion网站调用的Cold Fusion组件中有以下MYSQL查询。我有一个自定义采取,基本上为以下字段构建一个布尔查询:“PlaceName,Country,Adm1,adm2,adm3,locality”。如何加快复杂的MYSQL查询?
<!--- SEARCH PLACES 2--->
<cffunction name="searchPlaces_full" access="public" returntype="query">
<cfargument name="q" type="string" required="yes">
<CF_BOOLSEARCH searchterm="#arguments.q#" field="PlaceName,Country,Adm1,adm2,adm3,locality " booloperator="and">
<cfquery name="GetPlaces" datasource="#application.settings.dsn#">
SELECT
places.CatID,
places.PlaceName,
places.PlaceID,
places.Address1,
places.PostalCode,
places.Locality,
places.Address2,
places.ImageThumb,
places.Adm1,
places.Country,
places.Adm2,
places.Adm3,
places.contributorid,
places.lng,
places.lat,
places.verified,
places.verified_by,
places.verified_date
FROM places INNER JOIN places_cats ON places.PlaceID = places_cats.PlaceID
WHERE
<cfif len(trim(arguments.q))>
(#PreserveSingleQuotes(boolsearch)#)
<cfelse>
1=0
</cfif>
AND places_cats.CATID IN (#arguments.categories#)
GROUP BY
places.CatID,
places.PlaceName,
places.PlaceID,
places.Address1,
places.PostalCode,
places.Locality,
places.Address2,
places.ImageThumb,
places.Adm1,
places.Country,
places.Adm2,
places.Adm3,
places.contributorid,
places.lng,
places.lat,
places.verified,
places.verified_by,
places.verified_date
ORDER BY PlaceName
</cfquery>
<cfreturn getPlaces>
</cffunction>
数据库中有624227条记录。如果我搜索Chappaqua,实际运行的SQL如下所示:
SELECT
places.CatID,
places.PlaceName,
places.PlaceID,
places.Address1,
places.PostalCode,
places.Locality,
places.Address2,
places.ImageThumb,
places.Adm1,
places.Country,
places.Adm2,
places.Adm3,
places.contributorid,
places.lng,
places.lat,
places.verified,
places.verified_by,
places.verified_date
FROM places INNER JOIN places_cats ON places.PlaceID = places_cats.PlaceID
WHERE
(((PlaceName LIKE '%chappaqua%') OR (Country LIKE '%chappaqua%') OR (Adm1 LIKE '%chappaqua%') OR (adm2 LIKE '%chappaqua%') OR (adm3 LIKE '%chappaqua%') OR (locality LIKE '%chappaqua%')))
AND places_cats.CATID IN (1,21,15,32,16,26,29,27,28,25,75,89,38,5,36,88,87,31,33,24,35,37,90,39,40,34,30,9,8,7,11,20,19,96,97,95,13,17,14,12,3,2,4,84,85,86)
GROUP BY
places.CatID,
places.PlaceName,
places.PlaceID,
places.Address1,
places.PostalCode,
places.Locality,
places.Address2,
places.ImageThumb,
places.Adm1,
places.Country,
places.Adm2,
places.Adm3,
places.contributorid,
places.lng,
places.lat,
places.verified,
places.verified_by,
places.verified_date
ORDER BY PlaceName
我知道它很丑并且很复杂。大约需要1836ms运行。有没有更好的方法来编写查询或代码,以便在一秒之内加快返回的数据?
这里是解释上的SQL:
向我们显示您的索引。告诉我们你的'EXPLAIN'。 – Kermit
您似乎不使用聚合函数,那么GROUP BY是什么? – Strawberry
@Strawberry他们正试图获得'DISTINCT'行 – Taryn