我回过头来写一些C++,我老实说生锈了。如果我只是知道如何恰当地说出它,我会感觉到我会迅速回答我的问题,但是我仍然会很感激您的帮助。从构造函数初始化一个结构
sanitycheck.cpp:
#include <string>
using namespace std;
typedef struct STR_1 {
int val_a, val_b;
STR_1 (int a, int b)
{ val_a = a; val_b = b; }
} STR_1;
typedef struct STR_2{
string name;
STR_1 myStr1;
STR_2 (string n, STR_1 s)
{ name=n; myStr1 = s; }
} STR_2;
int main(){
return 0;
} // end main
当我试着使用g++ -o sanitycheck ./test/sanitycheck.cpp
编译我得到以下,
./test/sanitytest.cpp: In constructor ‘STR_2::STR_2(std::string, STR_1)’:
./test/sanitytest.cpp:25:3: error: no matching function for call to ‘STR_1::STR_1()’
{ name=name; myStr1 = &s; }
^
./test/sanitytest.cpp:25:3: note: candidates are:
./test/sanitytest.cpp:11:3: note: STR_1::STR_1(int*, int*)
STR_1 (int *a, int *b)
^
./test/sanitytest.cpp:11:3: note: candidate expects 2 arguments, 0 provided
./test/sanitytest.cpp:7:16: note: STR_1::STR_1(const STR_1&)
typedef struct STR_1 {
^
./test/sanitytest.cpp:7:16: note: candidate expects 1 argument, 0 provided
./test/sanitytest.cpp:25:23: error: no match for ‘operator=’ (operand types are ‘STR_1’ and ‘STR_1*’)
{ name=name; myStr1 = &s; }
^
./test/sanitytest.cpp:25:23: note: candidate is:
./test/sanitytest.cpp:7:16: note: STR_1& STR_1::operator=(const STR_1&)
typedef struct STR_1 {
^
./test/sanitytest.cpp:7:16: note: no known conversion for argument 1 from ‘STR_1*’ to ‘const STR_1&’
有一件事我不是明确的是STR_2
需要为什么会STR_1 myStr1;
首先调用STR_1
构造函数?我不能初始化这两种类型,
int main()
{
STR_1 bob = STR_1(5,6);
STR_2 tom = STR_2('Tom',bob);
return 0;
}
谢谢!
另一个重复,可能与更有用的答案:http://stackoverflow.com/questions/2685172/g-no-matching-function-call-error – juanchopanza
@juanchopanza http://stackoverflow.com/questions/926752/为什么要我更喜欢使用成员初始化列表可能是一个更好的重复,它显示了他的确切情况 – dwcanillas
@ juanchopanza的答案并没有真正解决我的问题。 – darkpbj