按Enter继续

Question

我有一个JDialog，它有两个字段，用户名和密码。我想使窗体像正常的那样按下输入就像按下继续。

我已经试过getRootPane().setDefaultButton(myButton);，但只有这似乎不起作用。

Answer 1

我已经尝试过getRootPane（）。setDefaultButton（myButton）;,但只有这似乎并没有工作。

比你要调用代码此按钮与方法

JButton#doClick();

，但更好的方式是使用KeyBindings

import java.awt.*; 
import java.awt.event.*; 
import javax.swing.*; 
import javax.swing.Timer; 
import javax.swing.border.EmptyBorder; 

public class Test { 

    private static final long serialVersionUID = 1L; 
    private JDialog dialog = new JDialog(); 
    private final JPanel contentPanel = new JPanel(); 
    private Timer timer1; 
    private JButton killkButton = new JButton("Kill JDialog"); 
    private JButton okButton = new JButton("OK"); 

    public Test() { 
     contentPanel.setLayout(new FlowLayout()); 
     contentPanel.setBorder(new EmptyBorder(5, 5, 5, 5)); 
     JPanel buttonPane = new JPanel(); 
     okButton.setActionCommand("OK"); 
     buttonPane.add(okButton); 
     killkButton.addActionListener(new ActionListener() { 

      public void actionPerformed(ActionEvent e) { 
       System.exit(0); 
      } 
     }); 
     killkButton.setActionCommand("Kill JDialog"); 
     buttonPane.add(killkButton); 
     dialog.setDefaultCloseOperation(JDialog.HIDE_ON_CLOSE); 
     dialog.addWindowListener(new WindowListener() { 

      public void windowOpened(WindowEvent e) { 
      } 

      public void windowClosing(WindowEvent e) { 
       startTimer(); 
      } 

      public void windowClosed(WindowEvent e) { 
      } 

      public void windowIconified(WindowEvent e) { 
      } 

      public void windowDeiconified(WindowEvent e) { 
      } 

      public void windowActivated(WindowEvent e) { 
      } 

      public void windowDeactivated(WindowEvent e) { 
      } 
     }); 
     dialog.setLayout(new BorderLayout()); 
     dialog.getRootPane().setDefaultButton(okButton); 
     dialog.add(buttonPane, BorderLayout.SOUTH); 
     dialog.add(contentPanel, BorderLayout.CENTER); 
     dialog.pack(); 
     dialog.setLocation(100, 100); 
     dialog.setVisible(true); 
     setKeyBindings(); 
    } 

    private void setKeyBindings() { 
     okButton.getInputMap(JComponent.WHEN_IN_FOCUSED_WINDOW).put(
       KeyStroke.getKeyStroke("ENTER"), "clickENTER"); 
     okButton.getActionMap().put("clickENTER", new AbstractAction() { 

      private static final long serialVersionUID = 1L; 

      @Override 
      public void actionPerformed(ActionEvent e) { 
       dialog.setVisible(false); 
       startTimer(); 
      } 
     }); 
    } 

    private void startTimer() { 
     timer1 = new Timer(1000, new AbstractAction() { 

      private static final long serialVersionUID = 1L; 

      @Override 
      public void actionPerformed(ActionEvent e) { 
       SwingUtilities.invokeLater(new Runnable() { 

        @Override 
        public void run() { 
         dialog.setVisible(true); 
        } 
       }); 
      } 
     }); 
     timer1.setDelay(500); 
     timer1.setRepeats(false); 
     timer1.start(); 
    } 

    public static void main(String[] args) { 
     SwingUtilities.invokeLater(new Runnable() { 

      @Override 
      public void run() { 
       Test test = new Test(); 
      } 
     }); 
    } 
} 

Answer 2

JButton button = ... 
JTextField password = ... 
ActionListener buttonListener = ... 

button.addActionListner(buttonListener); 
password.addActionListener(buttonListener); 

当在JTextField中按下enter键时，将触发一个操作事件。

Answer 3

你可以做到这一点通过添加动作监听你的textfield，就像这样。

JTextField field1 = new JTextField(); 

field1.addActionListener(new ActionListener() { 

     public void actionPerformed(ActionEvent e) { 

     //here is your method to continue 
     continue(); 

     } 

    });