我将数据发送到服务器阿贾克斯后JPA一对多的关系 - 外键未设置
var obj = {
'sub': 'this is a test.'
,'userName': 'dbdyd'
,'saveDate': new Date()
,'comments': [
{'comment':'1a', 'saveDate2': new Date(), 'seq2': null}
,{'comment':'2b', 'saveDate2': new Date(), 'seq2': null}
]
};
$.ajax({
url: '/cp/RestApi/Posts',
type: 'POST',
dataType: 'json',
contentType: 'application/json',
data: JSON.stringify(obj)
})
.done(function() {
console.log("success");
})
.fail(function() {
console.log("error");
});
我遇到了服务器错误。 foreignKey未设置为注释表。
INFO: Starting Coyote HTTP/1.1 on http-8080
Posts [seq=null, sub=this is a test., userName=dbdyd, saveDate=Sun Mar 13 09:05:46 KST 2016
, comments=[Comments [seq2=null, comment=2b, saveDate2=Sun Mar 13 09:05:46 KST 2016, posts=null], Comments [seq2=null, comment=1a, saveDate2=Sun Mar 13 09:05:46 KST 2016, posts=null]]]
Hibernate: insert into onnuricp.posts (save_date, sub, user_name) values (?, ?, ?)
Hibernate: insert into onnuricp.comments (comment, seq, save_date2) values (?, ?, ?)
09:05:47.315 [http-8080-1] ERROR org.hibernate.engine.jdbc.spi.SqlExceptionHelper - Column 'seq' cannot be null
Mar 13, 2016 9:05:47 AM org.apache.catalina.core.StandardWrapperValve invoke
数据库架构
Create Table: CREATE TABLE `posts` (
`seq` int(11) NOT NULL AUTO_INCREMENT COMMENT '게시판번호',
`sub` varchar(255) DEFAULT NULL COMMENT '제목',
`user_name` varchar(50) DEFAULT NULL COMMENT '작성자',
`save_date` datetime DEFAULT CURRENT_TIMESTAMP COMMENT '입력일자',
PRIMARY KEY (`seq`)
) ENGINE=InnoDB AUTO_INCREMENT=84 DEFAULT CHARSET=utf8 COMMENT='게시판'
CREATE TABLE `comments` (
`seq2` int(11) NOT NULL AUTO_INCREMENT COMMENT '댓글번호',
`comment` varchar(255) NOT NULL COMMENT '내용',
`save_date2` datetime DEFAULT CURRENT_TIMESTAMP COMMENT '작성일자',
`seq` int(11) NOT NULL COMMENT '게시판번호',
PRIMARY KEY (`seq2`),
KEY `FK_posts_TO_comments` (`seq`),
CONSTRAINT `FK_posts_TO_comments` FOREIGN KEY (`seq`) REFERENCES `posts` (`seq`) ON DELETE CASCADE ON UPDATE CASCADE
) ENGINE=InnoDB DEFAULT CHARSET=utf8 COMMENT='댓글'
;
我有一些问题,与春天的数据JPA。 @OneToMany的关系似乎是错的,但我不知道它。
@Entity
@Table(name = "posts")
public class Posts {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Basic(optional = false)
@Column(name = "seq")
private Integer seq;
@Column(name = "sub", nullable = true)
private String sub;
@Column(name = "user_name")
private String userName;
@Column(name = "save_date", nullable = false)
@Temporal(TemporalType.TIMESTAMP)
private Date saveDate;
@OneToMany(mappedBy = "posts", cascade = CascadeType.ALL)
private Set<Comments> comments;
}
@Entity
@Table(name = "comments")
public class Comments implements Serializable {
@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
@Basic(optional = false)
@Column(name = "seq2")
private Integer seq2;
@Column(name = "comment", nullable = false)
private String comment;
@Column(name = "save_date2", nullable = false)
@Temporal(TemporalType.TIMESTAMP)
private Date saveDate2;
@ManyToOne(optional = false)
@JoinColumn(name = "seq", referencedColumnName="seq", nullable = false)
private Posts posts;
}
保存对象(帖子和评论)。 和这样的服务实现。
Posts entity = new Post();
Posts savedEntity = repository.save(entity);
请帮助我与JPA Relationship。
thans to @ v.ladynev非常适合您的礼貌答案! ~~。 –
@永裕不客气。 –