2012-05-21 132 views
1

我想创建填充Admin和AdminHealthPlan表。jpa一对多关系无法例外

两者之间的关系是一对多关系(一个管理员可以拥有许多健康计划)。

Admin类被定义为如下:

@Entity 
@Table(name = "admin") 
@NamedQueries(value = { 
     @NamedQuery(name = "admin.getAdminById", query = "SELECT a " 
      + "from Admin a WHERE a.id=:id and deleted = 0"), 
     @NamedQuery(name = "admin.getAdminByEmail", query = "SELECT a " 
      + "from Admin a where a.email = :email and deleted = 0") }) 
public class Admin extends Persistent { 

    @Id 
    @GeneratedValue(strategy = GenerationType.AUTO) 
    private Long id; 
    @Column(name = "password") 
    private String password; 
    @Column(name = "email") 
    private String email; 
    @Column(name = "first_name") 
    private String firstName; 
    @Column(name = "last_name") 
    private String lastName; 
    @Column(name = "phone") 
    private String phone; 
    @OneToOne(mappedBy = "admin", fetch = FetchType.EAGER, 
      cascade = CascadeType.ALL) 
    private AdminRole role; 
    @OneToOne(mappedBy = "admin", fetch = FetchType.EAGER, 
      cascade = CascadeType.ALL) 
    private AdminPasswordToken passwordToken; 
    @OneToMany(mappedBy = "admin", fetch = FetchType.EAGER, 
      cascade = CascadeType.ALL) 
    private Set<AdminHealthPlan> healthPlans; 
    @Column(name = "deleted") 
    private Boolean deleted = false; 
    @Column(name = "security_question") 
    private Integer securityQuestion; 
    @Column(name = "security_answer") 
    private String securityAnswer; 

    public Admin() {} 

    // Getters/setters 
} 

AdminHealthPlan类定义如下。

@Entity 
@Table(name = "admin_health_plan") 
public class AdminHealthPlan implements Serializable { 

    private static final long serialVersionUID = 1L; 
    @Id 
    @GeneratedValue(strategy = GenerationType.AUTO) 
    private Long id; 
    @Column(name = "health_plan") 
    private String healthPlan; 
    @ManyToOne(cascade = CascadeType.ALL) 
    @JoinColumn(name = "admin_id", nullable = false) 
    private Admin admin; 
    @Column(name = "deleted") 
    private Boolean deleted = false; 

    public AdminHealthPlan() {} 

    public AdminHealthPlan(String healthPlan) { 
     this.healthPlan = healthPlan; 
    } 

    // Getters/setters 
} 

我从请求检索值并将其设置为管理对象,同样用于创建管理健康计划设置对象和管理对象设置它,最后发送对象保存到数据库创建管理对象。

它给例外如下

May 21, 2012 6:49:16 PM org.apache.catalina.core.StandardWrapperValve invoke 
SEVERE: Servlet.service() for servlet appServlet threw exception 
com.mysql.jdbc.exceptions.jdbc4.MySQLIntegrityConstraintViolationException: Column 'admin_id' cannot be null 
    at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) 
    at sun.reflect.NativeConstructorAccessorImpl.newInstance(NativeConstructorAccessorImpl.java:39) 
    at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(DelegatingConstructorAccessorImpl.java:27) 
    at java.lang.reflect.Constructor.newInstance(Constructor.java:513) 
    at com.mysql.jdbc.Util.handleNewInstance(Util.java:406) 
    at com.mysql.jdbc.Util.getInstance(Util.java:381) 
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:1015) 
    at com.mysql.jdbc.SQLError.createSQLException(SQLError.java:956) 
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3558) 
    at com.mysql.jdbc.MysqlIO.checkErrorPacket(MysqlIO.java:3490) 
    at com.mysql.jdbc.MysqlIO.sendCommand(MysqlIO.java:1959) 
    at com.mysql.jdbc.MysqlIO.sqlQueryDirect(MysqlIO.java:2109) 
    at com.mysql.jdbc.ConnectionImpl.execSQL(ConnectionImpl.java:2648) 
    at com.mysql.jdbc.PreparedStatement.executeInternal(PreparedStatement.java:2077) 
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2362) 
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2280) 
    at com.mysql.jdbc.PreparedStatement.executeUpdate(PreparedStatement.java:2265) 
    at org.apache.tomcat.dbcp.dbcp.DelegatingPreparedStatement.executeUpdate(DelegatingPreparedStatement.java:105) 
    at org.apache.tomcat.dbcp.dbcp.DelegatingPreparedStatement.executeUpdate(DelegatingPreparedStatement.java:105) 
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) 
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) 
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) 
    at java.lang.reflect.Method.invoke(Method.java:597) 
    at org.hibernate.engine.jdbc.internal.proxy.AbstractStatementProxyHandler.continueInvocation(AbstractStatementProxyHandler.java:122) 
    at org.hibernate.engine.jdbc.internal.proxy.AbstractProxyHandler.invoke(AbstractProxyHandler.java:81) 
    at $Proxy70.executeUpdate(Unknown Source) 

WS

创建管理员和AdminHealthPlan对象:

private Admin createAdminDummyObject() { 
     Admin admin = new Admin(); 
     admin.setFirstName("Zuned"); 
     admin.setLastName("Ahmed"); 
     admin.setEmail("[email protected]"); 
     admin.setPhone("123-1234454"); 
     admin.setHealthPlans(getHealthPlans(admin)); 
     return admin; 
    } 

    private Set<AdminHealthPlan> getHealthPlans(Admin admin) { 
     Set<AdminHealthPlan> adminAHP = new HashSet<AdminHealthPlan>(); 
     AdminHealthPlan ahp = new AdminHealthPlan(); 
     ahp.setAdmin(admin); 
     ahp.setHealthPlan("Plan1"); 
     adminAHP.add(ahp); 
     return adminAHP; 
    } 

我用

getJpaTemplate().persist(t); 

坚持分贝。

任何机构可以告诉我我错过了什么吗?

回答

2

我将EclipseLink,所以我不知道,如果它这样做在休眠不同,但是这是我所看到的错误:

1 - 你没有@Column批注添加到的id属性管理实体。
2 - 我始终对pks使用GenerationType.IDENTITY。 3 - 在AdminHealthPlan表中,admin属性具有JoinColumn注释,但未包含referencedColumnName属性。它应该是这样的:@JoinColumn(name = "admin_id", referencedColumnName = "admin_id")
4-添加新AdminHealthPlan到管理实体,我建议你做到以下几点:创建一个名为“addAdminHealthPlan”管理类中的方法:

public void addAdminHealthPlan(AdminHealthPlan ahp) { 
    if(healthPlans == null) { 
      healthPlans = new HashSet<AdminHealthPlan>(); 
    } 
    ahp.setAdmin(this); 
    healthPlans.add(ahp); 
} 

我不t知道什么是getJpaTemplate()方法和什么是对象“t”,但这将是坚持管理员的逻辑:

Admin admin = createAdminDummyObject(); 
AdminHealthPlan ahp = new AdminHealthPlan(); 
ahp.setAdmin(admin); 
ahp.setHealthPlan("Plan1"); 
admin.addAdminHealthPlan(ahp); 
entityManager.persist(admin); 
+0

感谢您的回复问题是第4点。 –