方法的难度

我的代码似乎是部分工作的：我的意思是说，当我没有进入闰年，例如99年底，然后我选择2月2日它打印29天，我想打印28我有2个独立的方法，一个用来检查一年是否跳跃，另一个用来打印月份的日期，所以如果有人知道如何修复程序以提高效率并且不用闰年来显示28天，我会感激。谢谢。方法的难度

这里是我的代码：

import java.util.Scanner; 
public class LeapYearCheck 
{ 
    public static void main(String[] args) 
    { 
     LeapYearCheck.isLeapYear(); 
     LeapYearCheck.daysInMonth(); 
    } 

    static void isLeapYear() 
    { 
     Scanner input = new Scanner(System.in); 
     System.out.println("Enter a year: "); 
     int year = input.nextInt(); 

     if(year % 4 == 0 || year % 400 ==0) 
     { 
      System.out.println(year + " is leap year:"); 
     } 
     else 
     { 
      System.out.println(year + " is not leap year:"); 
     } 
    } 

    static void daysInMonth() 
    { 
     Scanner input = new Scanner(System.in); 
     System.out.println("Enter a month :"); 
     int month = input.nextInt(); 

     if (month == 2) 
     { 
      System.out.println("There are 29 days in February: "); 
     } 
     else if(month == 1) 
     { 
      System.out.println("The are 31 days in January "); 
     } 
     else if(month == 2) 
     { 
      System.out.println("The are 28 days in February "); 
     } 
     else if(month == 3) 
     { 
      System.out.println("The are 31 days in March "); 
     } 
     else if(month == 4) 
     { 
      System.out.println("The are 30 days in April"); 
     } 
     else if(month == 5) 
     { 
      System.out.println("The are 31 days in May "); 
     } 
     else if(month == 6) 
     { 
      System.out.println("The are 30 days in June "); 
     } 
     else if(month == 7) 
     { 
      System.out.println("The are 31 days in July "); 
     } 
     else if(month == 8) 
     { 
      System.out.println("The are 31 days in August "); 
     } 
     else if(month == 9) 
     { 
      System.out.println("The are 30 days in September "); 
     } 
     else if(month == 10) 
     { 
      System.out.println("The are 31 days in October "); 
     } 
     else if(month == 11) 
     { 
      System.out.println("The are 30 days in November "); 
     } 
     else if(month == 12) 
     { 
      System.out.println("The are 31 days in December "); 
     } 
     else 
     { 
      System.out.println("Invalid Month, Please enter a number between 1 & 12 Merci: "); 
     } 
    } 
}

来源

2011-10-31 Kiril

这是功课吗？你可以使用joda和它的'DateTime'类以更简洁的方式实现这一点。 –

你可以自由使用Java库吗？加上请将if-else与switch-case替换为启动器。 –

你闰年检查是错误的。您应该使用

if((year%100 != 0 && year%4 == 0) || year % 400 ==0))

来源

2011-10-31 12:20:26 hovanessyan

谢谢你hovanessyan看来你的解决方案工作得更好 – Kiril

它将始终打印

共有29天，2月：

因为第一检查如下：

if (month == 2) 
      { 
      System.out.println("There are 29 days in February: "); 
      }

另外，正确的方法来检查飞跃是啊R：

if ((year % 400 == 0) || (year % 100 != 0 && year % 4 == 0)) { 
    //Leap year. 

}

正确的代码：

if (month == 2) { 
    if (LeapYearCheck.isLeapYear()) { 
     System.out.println("There are 29 days in this month."); 
    } else { 
     System.out.println("There are 28 days in this month."); 
    } 
}

让您isLeapYear()函数返回一个boolean（而不是void）。

来源

2011-10-31 12:21:27

我能做些什么来打印闰年的29天和28年的时候不是闰年，我知道如何在一种方法中做到这一点，但是当他们是separete我不知道 – Kiril

@Kiril，检查我的更新后的帖子。 –

谢谢精英绅士们有没有办法将if else的陈述结合起来，让他们更有效率，比如有一个30天一个31个，一个给其他人？ – Kiril

除了hovanessyan的suggestion之外，请注意，有关年份是否为闰年的信息在isLeapYear函数的范围内保留并丢失。例如，这个函数应该返回一个布尔值，并且在daysInMonth之内被调用，所以daysInMonth可以相应地返回28或29。使用Map也可以帮助简化巨大的if-else块。

来源

2011-10-31 12:21:55

这只是使纠结的混乱更糟糕，现在，不是吗？ –

确实。这是一个压倒性的混乱。修正它，至少不会增加悲剧的规模？ –

我想感谢大家的时间和精力。我真的很感激它，因为没有人可以问！ – Kiril

简而言之：daysInMonth()方法需要知道它是哪一年，然后如果月份数是2，则需要检查它是否是闰年。修改您的方法以接受年份和/或月份作为参数而不是提示，然后在main()中提示输入年份和月份，并将必要的数据传递给每个方法。

来源

2011-10-31 12:22:09

谢谢欧内斯特弗里德曼希尔！ – Kiril

首先ü进入29天如果月数为2

if (month == 2) 
     { 
     System.out.println("There are 29 days in February: "); 
     }

来源

2011-10-31 12:23:43 vikas27

试试这个代码....

import java.util.Scanner; 
public class LeapYearCheck { 
static boolean isleep; 
public static void main(String[] args) { 
    LeapYearCheck.isLeapYear(); LeapYearCheck.daysInMonth(); 
    } 
static void isLeapYear() { 
    Scanner input = new Scanner(System.in); 
    System.out.println("Enter a year: "); 
    int year = input.nextInt(); 

     if(year % 4 == 0 || year % 400 ==0) 
     { 
      isleep=true; 
     System.out.println(year + " is leap year:"); 
     } 
     else 
     { 
      isleep=false; 
      System.out.println(year + " is not leap year:"); 
     } 
    } 
     static void daysInMonth() 
     { 
     Scanner input = new Scanner(System.in); 
     System.out.println("Enter a month :"); 
     int month = input.nextInt(); 
     if (month == 2) 
     { 
      if(isleep) 
      System.out.println("There are 29 days in February: "); 
      else 
       System.out.println("There are 28 days in February: "); 
     } 
     else if(month == 1) 
     { 
      System.out.println("The are 31 days in January "); 
     } 

     else if(month == 3) 
     { 
      System.out.println("The are 31 days in March "); 
     } 
     else if(month == 4) 
     { 
      System.out.println("The are 30 days in April"); 
     } 
     else if(month == 5) 
     { 
      System.out.println("The are 31 days in May "); 
     } 
     else if(month == 6) 
     { 
      System.out.println("The are 30 days in June "); 
     } 
     else if(month == 7) 
     { 
      System.out.println("The are 31 days in July "); 
     } 
     else if(month == 8) 
     { 
      System.out.println("The are 31 days in August "); 
     } 
     else if(month == 9) 
     { 
      System.out.println("The are 30 days in September "); 
     } 
     else if(month == 10) 
     { 
      System.out.println("The are 31 days in October "); 
     } 
     else if(month == 11) 
     { 
      System.out.println("The are 30 days in November "); 
     } 
     else if(month == 12) 
     { 
      System.out.println("The are 31 days in December "); 
     } 
     else 
     { 
      System.out.println("Invalid Month, Please enter a number between 1 & 12 Merci: "); 
     } 
     }

}

来源

2011-10-31 12:23:59

当你输入年份和月份时，你需要再次输入年份和月份，而不是在第一次输入后给出结果 – Kiril

import java.util.Scanner; 
public class LeapYearCheck 
{ 
    public static boolean leap=false; 
public static void main(String[] args) 
{ 
    LeapYearCheck.leap=LeapYearCheck.isLeapYear(); 
    LeapYearCheck.daysInMonth(); 
} 
    static boolean isLeapYear() 
    { 
     Scanner input = new Scanner(System.in); 
     System.out.println("Enter a year: "); 
     int year = input.nextInt(); 

     if(year % 4 == 0 || year % 400 ==0) 
     { 
     System.out.println(year + " is leap year:"); 
     return true; 
     } 
     else 
     { 
      System.out.println(year + " is not leap year:");return false; 
     }return false; 
    } 
     static void daysInMonth() 
     { 
     Scanner input = new Scanner(System.in); 
     System.out.println("Enter a month :"); 
     int month = input.nextInt(); 
      if(month == 1) 
     { 
      System.out.println("The are 31 days in January "); 
     } 
     else if(month == 2) 
     {if(leap==true){ 
      System.out.println("The are 29 days in February ");} 
     else{System.out.println("The are 28 days in February ");}} 
     } 
     else if(month == 3) 
     { 
      System.out.println("The are 31 days in March "); 
     } 
     else if(month == 4) 
     { 
      System.out.println("The are 30 days in April"); 
     } 
     else if(month == 5) 
     { 
      System.out.println("The are 31 days in May "); 
     } 
     else if(month == 6) 
     { 
      System.out.println("The are 30 days in June "); 
     } 
     else if(month == 7) 
     { 
      System.out.println("The are 31 days in July "); 
     } 
     else if(month == 8) 
     { 
      System.out.println("The are 31 days in August "); 
     } 
     else if(month == 9) 
     { 
      System.out.println("The are 30 days in September "); 
     } 
     else if(month == 10) 
     { 
      System.out.println("The are 31 days in October "); 
     } 
     else if(month == 11) 
     { 
      System.out.println("The are 30 days in November "); 
     } 
     else if(month == 12) 
     { 
      System.out.println("The are 31 days in December "); 
     } 
     else 
     { 
      System.out.println("Invalid Month, Please enter a number between 1 & 12 Merci: "); 
     } 
     }

}

你可以检查。我还没有编译它

来源

2011-10-31 12:24:19 Kris

你需要知道今年还有一个月的计算天数：

public static void main(String[] args) { 
    Scanner input = new Scanner(System.in); 
    System.out.println("Enter a year: "); 
    int year = input.nextInt(); 
    if (LeapYearCheck.isLeapYear(year)) { 
     System.out.println(year + " is leap year:"); 
    } else { 
     System.out.println(year + " is not leap year:"); 
    } 
    System.out.println("Enter a month :"); 
    int month = input.nextInt(); 
    System.out.println("There are " + daysInMonth(year, month) + " in month"); 
} 

static boolean isLeapYear(int year) { 
    return (year % 4 == 0) && !(year % 100 == 0) || (year % 400 == 0); 
} 

static int daysInMonth(int year, int month) { 
    if (month == 1) { 
     return 31; 
    } else if (month == 2) { 
     if (isLeapYear(year)) { 
      return 29; 
     } else { 
      return 28; 
     } 
    } else if (month == 3) { 
     return 31; 
    } else if (month == 4) { 
     return 30; 
    } else if (month == 5) { 
     return 31; 
    } else if (month == 6) { 
     return 30; 
    } else if (month == 7) { 
     return 31; 
    } else if (month == 8) { 
     return 31; 
    } else if (month == 9) { 
     return 30; 
    } else if (month == 10) { 
     return 31; 
    } else if (month == 11) { 
     return 30; 
    } else if (month == 12) { 
     return 31; 
    } else { 
     throw new IllegalArgumentException(
       "Invalid Month, Please enter a number between 1 & 12 Merci: "); 
    } 
}

来源

2011-10-31 12:29:24

谢谢Maurice Perry！ – Kiril

使用的java.util.Calendar类，你会被罚款所有的时间。

来源

2011-10-31 12:32:07 fmucar

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