我创建了一个脚本,根据所选选项显示结果。代替Android的“if else”逻辑的替代编码
我需要:A,B,C,d(0,1,-1)
int A = 0;
int B = 0;
int C = 0;
int D = 0;
Ansver将16组合中的一个。
if A = 1 = A1;
if A = -1 = A2;
if B = 1 = B1;
if B = -1 B2;
if C = 1 = C1;
If C = -1 = C2;
If D = 1 = D1;
if D = -1 = D1;
A1;B1;C1;D1 = Nr1
A1;B1;C1;D2 = Nr2
A1;B1;C2;D1 = Nr3
A1;B1;C2;D2 = Nr4
A1;B2;C1;D1 = Nr5
A1;B2;C1;D2 = Nr6
A1;B2;C2;D1 = Nr7
A1;B2;C2;D2 = Nr8
A2;B1;C1;D1 = Nr9
A2;B1;C1;D2 = Nr10
A2;B1;C2;D1 = Nr11
A2;B1;C2;D2 = Nr12
A2;B2;C1;D1 = Nr13
A2;B2;C1;D2 = Nr14
A2;B2;C2;D1 = Nr15
A2;B2;C2;D2 = Nr16
我想显示潜在的变体。
当你按下的组合:A1, B1 = "Nr1,Nr2,Nr3,Nr4"
当你按下的组合:A1, D1 = "Nr1,Nr3,Nr5,Nr7"
以后会更多的变数E
,F
,G
,H
....等等。但问题的答案将仅16
可能是什么逻辑,我有点卡住了?
If/Else
似乎太长。
if (A == 1) {
if (B == 1) {
if (C == 1) {
if (D == 1) {
scoreTeamA = "Nr1"; //A1,B1,C1,D1
} else if (D == -1) {
scoreTeamA = "Nr2"; //A1,B1,C1,D2
} else scoreTeamA = "Nr1, Nr2"; //A1,B1,C1
} else if (B == 1) {
if (D == 1) {
scoreTeamA = "Nr3"; //A1,B1,C1,D1
} else if (D == -1) {
scoreTeamA = "Nr4"; //A1,B1,C1,D2
} else scoreTeamA = "Nr3,Nr4"; //A1,B1,C2
} else scoreTeamA = "Nr1,Nr2,Nr3,Nr4"; //A1,B1
} else if (B == -1) {
scoreTeamA = "Nr5,Nr6,Nr7,Nr8";//A1,B2
} else
scoreTeamA = "Nr1,Nr2,Nr3,Nr4,Nr5,Nr6,Nr7,Nr8"; //A1
} else if (A == -1) {
scoreTeamA = "Nr9,Nr10,Nr11,Nr12,Nr13,Nr14,Nr15,Nr16"; //A2
}
逻辑取决于你,你希望你的代码如何。 –