从一系列日期中获取所有排名前5的id（数组）

Question

我需要查询tableA中排名前5的值。如下面

select id, count(occurrence), date 
    from 
    (select id, unnest(value) as occurrence, date from tableA) as a 
    group by id, occurrence, date 
    order by occurrence desc 
    limit 5 

id | occurrence | date 
-----+-------+---------- 
330 | 11 | 20141015 
400 | 11 | 20141015 
390 | 10 | 20141015 
240 | 10 | 20141015 
501 | 10 | 20141015 

并收到的ID后，查询同一个表A来获取ID的所有值用于其它日期的范围是从20140101到20141015.

expected result: 

id | occurrence | date 
-----+-------+---------- 
330 | 11 | 20141015 
400 | 11 | 20141015 
390 | 10 | 20141015 
240 | 10 | 20141015 
501 | 10 | 20141015 
330 | 0 | 20141014 
400 | 1 | 20141014 
390 | 10 | 20141014 
240 | 15 | 20141014 
501 | 10 | 20141014 
330 | 11 | 20141013 
400 | 11 | 20141013 
390 | 11 | 20141013 
240 | 19 | 20141013 
501 | 10 | 20141013 

但我究竟该怎么办那？

我的PostgreSQL的版本是8.1，我不能使用分区（如果任何U想暗示）

---

编辑

select id, count(value) as occurrence, date 
from tableA 
where id = ANY(
    select array(
     select id 
     from (
      select date, unnest(id) as id 
      from tableA where date>='20140101' and date<='20141015' 
      )as a 
     ) 
) 
group by id, date 

不返回任何东西。我的阵列是否正确？

Answer 1

您可以尝试从dt> 20140101和dt < 20141015以及row_num < = 5的表中选择某项，这会给您正确的答案。

Answer 2

select id, count(value) as occurrence, date 
from t 
where id in (
    select id 
    from (
     select id, count(value) as occurrence, date 
     from t 
     group by id, date 
     order by occurrence desc 
     limit 5 
    ) s 
) q 
group by id, date