XML数据集转换

Question

嗨我是新来的XSLT我想转换Xml数据集，其中学生名称映射从一个XML，其中有学生名称和卷号的数据集。 classwise。

我想要使用xslt，但我不想添加所有标记只是要映射的列名称标记，并将其他列按原样添加。

这里是输入输出数据集示例。 xml是来自c＃代码的正常dataset.writexml。

表1：

RollNo Sub1 Sub2 Sub3 Sub4 
1   65 89 67 34 
2   67 86 67 76 
3   86 67 78 45 
4   56 56 87 56 
5   76 56 56 78 

表2

Name  Sub1 Sub2 Sub3 Sub4 
Aman  65 89 67 34 
Ankit  67 86 67 76 
Om  86 67 78 45 
Narendra 56 56 87 56 
Faisal 76 56 56 78 

这是要用于转化的的Xml

映射XML

<?xml version="1.0" standalone="yes"?> 
<School> 
    <Class Name="Class1"> 
     <StudentData Name="Aman" RollNo="1" /> 
     <StudentData Name="Ankit" RollNo="2" /> 
     <StudentData Name="Om" RollNo="3" /> 
     <StudentData Name="Narendra" RollNo="4" /> 
     <StudentData Name="Faisal" RollNo="5" />  
    </Class> 
    <Class Name="Class2"> 
     <StudentData Name="Abhinav" RollNo="1" /> 
     <StudentData Name="Abhishek" RollNo="2" /> 
     <StudentData Name="Ishaan" RollNo="3" /> 
     <StudentData Name="Mayank" RollNo="4" /> 
     <StudentData Name="Bhavana" RollNo="5" />  
    </Class> 
</School> 

XSLT创建至今

<?xml version="1.0" encoding="UTF-8"?> 

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs" 
      xmlns:msxsl="urn:schemas-microsoft-com:xslt" xmlns:user="http://www.contoso.com"> 
    <xsl:output method="xml" encoding="UTF-8" indent="yes" omit-xml-declaration="yes"/> 

    <xsl:template match="/"> 
    <DocumentElement> 
     <xsl:for-each select="//Comparision"> 
     <xsl:if test ="number(COL7)"> 
     <PositionMaster> 

        <xsl:variable name="RollNo" select="normalize-space(COL1)"/> 
        <xsl:variable name="Name"> 
         <xsl:value-of select="document('../../../MappingFiles/Mapping.xml')/School/PB[@Name='Class1']/TagData[@RollNo=$RollNo]/@Name"/> 
        </xsl:variable> 
        <Name> 
         <xsl:choose> 
          <xsl:when test="$Name!=''"> 
           <xsl:value-of select="$Name"/> 
          </xsl:when> 
          <xsl:otherwise> 
           <xsl:value-of select="$Name"/> 
          </xsl:otherwise> 
         </xsl:choose> 
        </Name> 
      </PositionMaster> 
     </xsl:if > 
     </xsl:for-each> 
    </DocumentElement> 
    </xsl:template> 
</xsl:stylesheet> 

感谢 阿曼

Answer 1

只是作为一个例子，下面给出输入XML：

<Table> 
    <Student> 
     <RollNo>1</RollNo> 
     <Sub1>11</Sub1> 
     <Sub2>12</Sub2> 
     <Sub3>13</Sub3> 
    </Student> 
    <Student> 
     <RollNo>2</RollNo> 
     <Sub1>21</Sub1> 
     <Sub2>22</Sub2> 
     <Sub3>23</Sub3> 
    </Student> 
    <Student> 
     <RollNo>3</RollNo> 
     <Sub1>31</Sub1> 
     <Sub2>32</Sub2> 
     <Sub3>33</Sub3> 
    </Student> 
    <Student> 
     <RollNo>4</RollNo> 
     <Sub1>41</Sub1> 
     <Sub2>42</Sub2> 
     <Sub3>43</Sub3> 
    </Student> 
    <Student> 
     <RollNo>5</RollNo> 
     <Sub1>51</Sub1> 
     <Sub2>52</Sub2> 
     <Sub3>53</Sub3> 
    </Student> 
</Table> 

，并命名为 “Mapping.xml” 外部文件：

<?xml version="1.0" standalone="yes"?> 
<School> 
    <Class Name="Class1"> 
     <StudentData Name="Aman" RollNo="1" /> 
     <StudentData Name="Ankit" RollNo="2" /> 
     <StudentData Name="Om" RollNo="3" /> 
     <StudentData Name="Narendra" RollNo="4" /> 
     <StudentData Name="Faisal" RollNo="5" />  
    </Class> 
    <Class Name="Class2"> 
     <StudentData Name="Abhinav" RollNo="1" /> 
     <StudentData Name="Abhishek" RollNo="2" /> 
     <StudentData Name="Ishaan" RollNo="3" /> 
     <StudentData Name="Mayank" RollNo="4" /> 
     <StudentData Name="Bhavana" RollNo="5" />  
    </Class> 
</School> 

th E采用的样式表：

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/> 
<xsl:strip-space elements="*"/> 

<xsl:param name="class">Class2</xsl:param> 

<xsl:key name="student" match="StudentData" use="concat(@RollNo, '|' , ../@Name)" /> 

<!-- identity transform --> 
<xsl:template match="@*|node()"> 
    <xsl:copy> 
     <xsl:apply-templates select="@*|node()"/> 
    </xsl:copy> 
</xsl:template> 

<xsl:template match="RollNo"> 
    <Name> 
     <xsl:variable name="RollNo" select="." /> 
     <!-- switch context to the other document in order to use key --> 
     <xsl:for-each select="document('Mapping.xml')"> 
      <xsl:value-of select="key('student', concat($RollNo, '|' , $class))/@Name" /> 
     </xsl:for-each> 
    </Name> 
</xsl:template> 

</xsl:stylesheet> 

将返回：

<?xml version="1.0" encoding="UTF-8"?> 
<Table> 
    <Student> 
     <Name>Abhinav</Name> 
     <Sub1>11</Sub1> 
     <Sub2>12</Sub2> 
     <Sub3>13</Sub3> 
    </Student> 
    <Student> 
     <Name>Abhishek</Name> 
     <Sub1>21</Sub1> 
     <Sub2>22</Sub2> 
     <Sub3>23</Sub3> 
    </Student> 
    <Student> 
     <Name>Ishaan</Name> 
     <Sub1>31</Sub1> 
     <Sub2>32</Sub2> 
     <Sub3>33</Sub3> 
    </Student> 
    <Student> 
     <Name>Mayank</Name> 
     <Sub1>41</Sub1> 
     <Sub2>42</Sub2> 
     <Sub3>43</Sub3> 
    </Student> 
    <Student> 
     <Name>Bhavana</Name> 
     <Sub1>51</Sub1> 
     <Sub2>52</Sub2> 
     <Sub3>53</Sub3> 
    </Student> 
</Table>