2012-09-28 215 views
0

我有一个XML像下面C#反序列化对象

 string input = 
@"<g1:Person xmlns:g1=""http://api.google.com/staticInfo/""> 
    <g1:Id>005008</g1:Id> 
    <g1:Infolist> 
<g1:Info><g1:Title>a</g1:Title></g1:Info>  
<g1:Info<g1:Title>b</g1:Title></g1:Info>  
<g1:Info><g1:Title>c</g1:Title></g1:Info> 
<g1:overview>there are three chaters.</g1:overview> 
    </g1:Infolist> 
    <g1:age>23</g1:age> 
    </g1:Person>"; 

我定义对象,但我不知道放在哪里/人/ Infolist /概述。这个属性如何定义。在哪里放。

[XmlRoot(ElementName = "Person", Namespace = "http://api.google.com/staticInfo/")] 
    public class Person 
    { 

     public int Id { get; set; } 

     public int age { get; set; } 

     [XmlElement(ElementName = "Infolist", Namespace = "http://api.google.com/staticInfo/")] 
     public List<Info> Infolist {get;set; } 
    } 

    public class Info 
    { 
     public int Title { get; set; } 
    } 

回答

1
//------------------------------------------------------------------------------ 
// <auto-generated> 
//  This code was generated by a tool. 
//  Runtime Version:4.0.30319.269 
// 
//  Changes to this file may cause incorrect behavior and will be lost if 
//  the code is regenerated. 
// </auto-generated> 
//------------------------------------------------------------------------------ 

using System.Xml.Serialization; 

// 
// This source code was auto-generated by xsd, Version=4.0.30319.1. 
// 


/// <remarks/> 
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")] 
[System.SerializableAttribute()] 
[System.Diagnostics.DebuggerStepThroughAttribute()] 
[System.ComponentModel.DesignerCategoryAttribute("code")] 
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true, Namespace="http:=//api.google.com/staticInfo/")] 
[System.Xml.Serialization.XmlRootAttribute(Namespace="http:=//api.google.com/staticInfo/", IsNullable=false)] 
public partial class Person { 

    /// <remarks/> 
    public ushort Id; 

    /// <remarks/> 
    public PersonInfolist Infolist; 

    /// <remarks/> 
    public byte age; 
} 

/// <remarks/> 
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "4.0.30319.1")] 
[System.SerializableAttribute()] 
[System.Diagnostics.DebuggerStepThroughAttribute()] 
[System.ComponentModel.DesignerCategoryAttribute("code")] 
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType=true, Namespace="http:=//api.google.com/staticInfo/")] 
public partial class PersonInfolist { 

    /// <remarks/> 
    [System.Xml.Serialization.XmlElementAttribute("Info")] 
    public string[] Info; 

    /// <remarks/> 
    public string overview; 
} 

步骤:

  • 你的XML粘贴到Visual Studio中
  • 单击XML新的XML文件 - >创建模式
  • 保存模式文件的磁盘
  • 开放visual studio命令提示符
  • 执行命令:xsd /classes /fields so.xsd

这可能是获得结果的很多方法之一。我喜欢让工具生成我的代码 - 他们从不犯错误。

+0

自动生成?什么是工具,man?我手动定义许多类 – user1682718

+0

xsd.exe是工具。你可以使用它的输出来帮助你手动定义你的类。否则别人也许会回答你的问题太好了...祝你好运 –

+0

wow.awesome男人,谢谢你,发布给我更多的知识 – user1682718