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我有这样的团队表(可以是一个项目表以及)和成员表获得团队成员在一个特定的团队在MySQL
+-----------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-----------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| team_name | varchar(100) | NO | UNI | NULL | |
| team_desc | varchar(200) | NO | | NULL | |
| createdby | varchar(100) | NO | | NULL | |
+-----------+--------------+------+-----+---------+----------------+
和成员表
+-------------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| firstname | varchar(45) | NO | | NULL | |
| lastname | varchar(45) | NO | | NULL | |
| address | varchar(200) | NO | | NULL | |
| city | varchar(45) | NO | | NULL | |
| state | varchar(45) | NO | | NULL | |
| country | varchar(45) | NO | | NULL | |
| email | varchar(45) | NO | | NULL | |
| phone | varchar(10) | YES | | NULL | |
| experience | varchar(45) | NO | | NULL | |
| designation | varchar(45) | NO | | NULL | |
| username | varchar(45) | NO | | NULL | |
| password | varchar(45) | NO | | NULL | |
+-------------+--------------+------+-----+---------+----------------+
和这两个表加入了这个teams_members表,
+------------------+---------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+------------------+---------+------+-----+---------+----------------+
| teams_members_id | int(11) | NO | PRI | NULL | auto_increment |
| teams_id | int(11) | NO | MUL | NULL | |
| members_id | int(11) | NO | MUL | NULL | |
+------------------+---------+------+-----+---------+----------------+
我想要做的是让一个特定的团队成员。我很困惑,我怎么会做这个(可能是我哑然:P)
SELECT *
FROM teams_members tm, members m, teams t
WHERE tm.members_member_id = m.id
AND t.team_name='team name can be anything'
AND tm.id = t.id
它返回0的结果。我可能在哪里错了?
我实际上正在考虑使用'INNER JOIN'。这个技巧谢谢你! – user1601973