SQL错误：SQLSTATE [23000]：完整性约束违规：1452无法添加或更新子行：外键约束失败

我对PHP和SQL有一些问题，PHP对我来说是新手，我缺少SQL。SQL错误：SQLSTATE [23000]：完整性约束违规：1452无法添加或更新子行：外键约束失败

我想在我的数据库的表中添加值：值可以从表单中获取，也可以从其他表中获取（如FK）。

这里的数据库：

create database AAA; 
use AAA; 

create table assure(
id_assure varchar(13) not null, 
nom varchar(20), 
adresse varchar(50), mdp varchar(60), 
primary key(id_assure)); 

create table vehicule(
id_vehicule varchar(13) not null, 
immatriculation varchar(7), 
masse int(4), 
volume int(4), 
id_assure varchar(13) not null, 
primary key(id_vehicule), 
foreign key(id_assure) references assure(id_assure)); 

create table reparation(
id_reparation varchar(13) not null, 
libelle varchar(100), 
couts int(5), 
primary key(id_reparation), 
id_vehicule varchar(13) not null, 
foreign key(id_vehicule) references vehicule(id_vehicule)); 


create table sinistre(
id_sinistre varchar(13) not null, 
libelle varchar(100), 
date_sinistre date, 
heure_sinistre time, 
primary key(id_sinistre), 
id_vehicule varchar(13) not null, 
foreign key(id_vehicule) references vehicule(id_vehicule)); 

create table dossier(
id_dossier varchar(13) not null, 
primary key(id_dossier), 
id_sinistre varchar(13) not null, 
foreign key(id_sinistre) references sinistre(id_sinistre)); 

create table contrat_assurance(
id_assurance varchar(13) not null, 
primary key(id_assurance), 
id_assure varchar(13) not null, 
id_vehicule varchar(13) not null, 
foreign key(id_assure) references assure(id_assure), 
foreign key(id_vehicule) references vehicule(id_vehicule)); 

create table type_garantie(
code_garantie varchar(13) not null, 
libelle varchar(100), 
franchise int(3) , 
primary key(code_garantie), 
id_assurance varchar(13) not null, 
id_reparation varchar(13) not null, 
foreign key(id_reparation) references reparation(id_reparation), 
foreign key(id_assurance) references contrat_assurance(id_assurance)); 


DELIMITER // 
CREATE TRIGGER trigfranchise 
BEFORE INSERT ON type_garantie 
for EACH ROW 
BEGIN 
    IF NEW.franchise not between 150 and 600 

    THEN 
    SET NEW.franchise = NULL ; 
    END IF; 
END ;// 
DELIMITER ; 

DELIMITER // 
CREATE TRIGGER trigfranchise1 
BEFORE UPDATE ON type_garantie 
for EACH ROW 
BEGIN 
    IF NEW.franchise not between 150 and 600 

    THEN 
    SET NEW.franchise = OLD.franchise ; 
    END IF; 
END ;// 
DELIMITER ;

我的第一种形式发送的值来确保表，它工作正常。我的第二个意思是将价值发送到vehicule和contrat_assurance表;

ERREUR：检查的形式，浏览器显示后SQLSTATE [23000]：完整性约束违规：1452不能添加或更新子行，外键约束失败（aaavehicule，约束vehicule_ibfk_1外国。 KEY （id_assure）参考assure（id_assure））

我的PHP代码如下因素：

try 
     { 
      $nom=mysql_real_escape_string($_POST["nom"]); 
      $mdp=mysql_real_escape_string($_POST["mdp"]); 
      $imma=mysql_real_escape_string($_POST["immatriculation"]); 

      $pdo_options[PDO::ATTR_ERRMODE] = PDO::ERRMODE_EXCEPTION; 
      $bdd = new PDO('mysql:host=localhost;dbname=AAA', 'root', '', $pdo_options); 

      $req = $bdd->prepare('INSERT INTO vehicule (id_vehicule, immatriculation) VALUES(:id_vehicule, :immatriculation)'); 

      $req->execute(array(
      'id_vehicule' => uniqid(), 
      'immatriculation' => $imma 
      )); 


      $req2 = $bdd->prepare("INSERT INTO vehicule (id_assure) SELECT id_assure FROM assure WHERE nom =\"$nom\" AND mdp =\"$mdp\""); 



      $req3 = $bdd->prepare('INSERT INTO contrat_assurance (id_assurance) VALUES(:id_assurance)'); 
      $req4 = $bdd->prepare("INSERT INTO contrat_assurance (id_assure, id_vehicule) SELECT id_assure, id_vehicule FROM vehicule WHERE immatriculation =\"$imma\""); 

      $req3->execute(array(
      'id_assurance' => uniqid() 

      )); 



     }

其实，我发现有关这个错误的其他主题，由于我的技能很差，我无法将答案与我的问题相匹配。

对不起，英文和法文表名不好。

谢谢您的阅读！

更新：我试图通过终端（无PHP）添加值，它的工作，因此我的PHP代码是错误的。

UPDATE2：这里是PHP代码插入id_assure为保证表（这是在驱动车辆表中的FK）：

try 
     { 
      $pdo_options[PDO::ATTR_ERRMODE] = PDO::ERRMODE_EXCEPTION; 
      $bdd = new PDO('mysql:host=localhost;dbname=AAA', 'root', '', $pdo_options); 

      $req = $bdd->prepare('INSERT INTO assure(id_assure, nom, adresse, mdp) VALUES(:id_assure, :nom, :adresse, :mdp)'); 
      $req->execute(array(
      'id_assure' => uniqid(), 
      'nom' => $_POST['nom'], 
      'adresse' => $_POST['adresse'], 
      'mdp' => $_POST['mdp'] 
      )); 


     } 
     catch(Exception $e) 
     { 
      die('Erreur : '.$e->getMessage()); 
     }

来源

2015-05-25 Aleks