0
我想在HTML中显示http://services.xyz.com/tours.asmx/Sample?type=2&CityID=1146&days=4这个数组数据。JSON数组foreach循环显示提供给foreach的无效参数()
这里是我的代码:
ini_set("display_errors", 1);
$url = "http://services.xyz.com/tours.asmx/Sample?type=2&CityID=1146&days=4";
$ch = curl_init($url);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_BINARYTRANSFER, 1);
//curl_setopt($ch, CURLOPT_POSTFIELDS, $fields); // set the fields to post
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); // make sure we get the response back
$xml = curl_exec($ch); // execute the post
curl_close($ch); // close our session
include "XMLParser.php";
$parser = new XMLParser();
$tour = $parser->parseString($xml);
print_r($tour);
//$errors = array_filter($tour);
if (empty($tour)) {
echo 'Error';
}else{
echo 'No Error';
}
//print_r($xml);
//var_dump($xml);
//echo $xml;
//$xmlfile = file_get_contents($tour);
$ob= simplexml_load_string($tour);
//$json = json_encode($ob);
$configData = json_decode($ob, true);
foreach($configData as $result){
echo '<tr>';
echo '<td>'.$result->name.'</td>';
echo '<td>'.$result->phone.'</td>';
echo '<td>'.$result->email.'</td>';
echo '</tr>';
}
我收到此错误Warning: Invalid argument supplied for foreach() in C:
请帮助我。 谢谢
该数组为空。在循环之前检查它 – Akintunde007
代码的图像在问题中是不可接受的。将实际代码放在这里 – apokryfos
您可能想要'json_decode'而不是'json_encode',因为API已经为您提供了一个JSON字符串。摆脱第24行,并用当前行中的$ ob替换'$ json'(这将是新行24)。 – ccKep