2012-05-09 36 views
1

我有一个用例,我需要为一次性使用动态地创建一个规则。规则是动态的,在更糟糕的情况下,每个迭代/请求可能会有所不同。因此,我无法储存它们。Drools - 更快地创建KnowlegeBuilder?

我目前对Drools的理解是,您需要创建一个KnowledgeBuilder,然后添加规则。

我按如下方式创建知识库。

private KnowledgeBase readKnowledgeBase() throws Exception { 
long t1 = System.currentTimeMillis(); 
    KnowledgeBuilder kbuilder = KnowledgeBuilderFactory.newKnowledgeBuilder(); 
long t11 = System.currentTimeMillis(); 


    kbuilder.add(org.drools.io.ResourceFactory.newByteArrayResource(getRule()), ResourceType.DRL); 

long t2 = System.currentTimeMillis(); 

    KnowledgeBuilderErrors errors = kbuilder.getErrors(); 
    if (errors.size() > 0) { 
     for (KnowledgeBuilderError error: errors) { 
      System.err.println(error); 
     } 
     throw new IllegalArgumentException("Could not parse knowledge."); 
    } 
long t3 = System.currentTimeMillis(); 

    KnowledgeBase kbase = KnowledgeBaseFactory.newKnowledgeBase(); 
long t4 = System.currentTimeMillis(); 

    kbase.addKnowledgePackages(kbuilder.getKnowledgePackages()); 
long t5 = System.currentTimeMillis(); 


    Collection<KnowledgePackage> kpackages = kbase.getKnowledgePackages(); 
      for (KnowledgePackage knowledgePackage : kpackages) { 
        System.out.println("Package -------- " + knowledgePackage.getName()); 
        Collection<Rule> rules = knowledgePackage.getRules(); 
        for (Rule rule : rules) { 
          System.out.println("****" + rule.getName()); 
        } 
      } 
long t6 = System.currentTimeMillis(); 

System.out.println((t11-t1) + " " + (t2-t11) + " " + (t3-t2) + " " + (t4-t3) + " " + (t5-t4) + " " + (t6-t5)+ " "); 

    return kbase; 
} 

基于定时登录只有这两个操作的时间的代码取大多数(超过80%)。有没有办法让它更快?或者有没有办法实现我的用例?

KnowledgeBuilder kbuilder = KnowledgeBuilderFactory.newKnowledgeBuilder(); 
kbuilder.add(org.drools.io.ResourceFactory.newByteArrayResource(getRule()), ResourceType.DRL); 
+0

有关于这对Drools的用户forum.http一些讨论://drools.46999.n3.nabble.com/Is-there-a-这样做,这个功能于Drools的-td3973888.html更快的方式 - 的 - –

回答

0

以下调用实际上将编译代码,也就是说,它会调用JDT Java编译器:

kbuilder.add(org.drools.io.ResourceFactory.newByteArrayResource(getRule())的ResourceType。博士升);

除非使用内部API,否则无法避免这种情况,实际上使用起来非常复杂。

有一个中间步骤是使用描述符构建器API生成规范模型。它会为你节省几个周期,但最重要的操作是java编译。使用DESCR生成器API的例子:

https://github.com/droolsjbpm/drools/blob/master/drools-compiler/src/test/java/org/drools/lang/api/DescrBuilderTest.java