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我最近发现我们可以使用Oracle的Max(Decode())函数来旋转表的结果。我已经执行了这个很好。但是,旋转表格只是我需要的解决方案的一部分。该转动功能结果是这样的:将连续数字计入一行
01,02,03,05,06,07,08,09,10,11,12,13,14,16,17,20,21,23,25
我真正需要的是这样的:
1-17, 20-21,23,25
我真的不知道该如何下手解决这一点,但到目前为止,我有以下查询:
SELECT DISTINCT
MAX(DECODE(wldw.wafernumber,'01', '01'))
|| MAX(DECODE(wldw.wafernumber,'02', ',02'))
|| MAX(DECODE(wldw.wafernumber,'03', ',03'))
|| MAX(DECODE(wldw.wafernumber,'04', ',04'))
|| MAX(DECODE(wldw.wafernumber,'05', ',05'))
|| MAX(DECODE(wldw.wafernumber,'06', ',06'))
|| MAX(DECODE(wldw.wafernumber,'07', ',07'))
|| MAX(DECODE(wldw.wafernumber,'08', ',08'))
|| MAX(DECODE(wldw.wafernumber,'09', ',09'))
|| MAX(DECODE(wldw.wafernumber,'10', ',10'))
|| MAX(DECODE(wldw.wafernumber,'11', ',11'))
|| MAX(DECODE(wldw.wafernumber,'12', ',12'))
|| MAX(DECODE(wldw.wafernumber,'13', ',13'))
|| MAX(DECODE(wldw.wafernumber,'14', ',14'))
|| MAX(DECODE(wldw.wafernumber,'15', ',15'))
|| MAX(DECODE(wldw.wafernumber,'16', ',16'))
|| MAX(DECODE(wldw.wafernumber,'17', ',17'))
|| MAX(DECODE(wldw.wafernumber,'18', ',18'))
|| MAX(DECODE(wldw.wafernumber,'19', ',19'))
|| MAX(DECODE(wldw.wafernumber,'20', ',20'))
|| MAX(DECODE(wldw.wafernumber,'21', ',21'))
|| MAX(DECODE(wldw.wafernumber,'22', ',22'))
|| MAX(DECODE(wldw.wafernumber,'23', ',23'))
|| MAX(DECODE(wldw.wafernumber,'24', ',24'))
|| MAX(DECODE(wldw.wafernumber,'25', ',25')) AS WAFERS
, 'history' as well
FROM a_wiplothistory wl
JOIN Container C ON (wl.containerid = c.containerid OR wl.containerid= c.splitfromid)
JOIN a_wiplotdetailshistory wld ON wl.wiplothistoryid = wld.wiplothistoryid
JOIN a_wiplotdetailswafershistory wldw ON wld.wiplotdetailshistoryid = wldw.wiplotdetailshistoryid
WHERE c.containername = :lot
感谢您的帮助。
对于复杂的条件,最好使用'case〜when'。 – ntalbs
hello ntalbs,你能给我一个关于如何开始这个的样本吗? – GianIsTheName
我误解了你的问题。如果你想把连续的数字减少到范围(例如:01,02,03 - > 1-3,和02,03,04 - > 2-4),那么'case〜when'不会帮助你。 – ntalbs