2011-09-23 54 views
2

首先,对于长时间的解释抱歉。我在PHP中有两个数组。第一个数组是一个对象数组。第二个数组是数组的数组。基本上,我想循环,并将该对象与其匹配的数组合并,并返回一个合并的对象。PHP如何合并与阵列阵列对象

参见以下对象结构的阵列的print_r()

Array 
(
[0] => stdClass Object 
    (
     [gear] => helloworld 
     [status] => running 
     [started] => 40 Minutes Ago 
     [start] => index.js 
     [route] => 127.0.0.1:3000 
     [parameters] => Array 
      (
      ) 

    ) 

[1] => stdClass Object 
    (
     [gear] => test 
     [status] => stopped 
     [started] => 
     [start] => index.js 
     [route] => 
     [parameters] => Array 
      (
      ) 

    ) 

[2] => stdClass Object 
    (
     [gear] => test2 
     [status] => stopped 
     [started] => 
     [start] => index.js 
     [route] => 
     [parameters] => Array 
      (
       [0] => first 
       [1] => second 
       [2] => third 
      ) 

    ) 

) 

见阵列结构的阵列的以下print_r()

Array 
(
[0] => Array 
    (
     [gear] => helloworld 
     [machine_id] => E6z5ekvQ 
     [created_by] => 10010 
     [modified_by] => 10010 
     [created] => 2011-09-22T16:30:11-07:00 
     [modified] => 2011-09-22T16:30:11-07:00 
    ) 

[1] => Array 
    (
     [gear] => test 
     [machine_id] => E6z5ekvQ 
     [created_by] => 10010 
     [modified_by] => 10010 
     [created] => 2011-09-22T16:44:25-07:00 
     [modified] => 2011-09-22T16:44:25-07:00 
    ) 

[2] => Array 
    (
     [gear] => test2 
     [machine_id] => E6z5ekvQ 
     [created_by] => 10010 
     [modified_by] => 10010 
     [created] => 2011-09-22T16:45:43-07:00 
     [modified] => 2011-09-22T16:45:43-07:00 
    ) 

) 

所以基本上两者的匹配键是gear。因此,我们应该与来自第一个目标的齿轮,与数组中的第二档,并返回类似:

stdClass Object 
    (
     [gear] => helloworld 
     [status] => running 
     [started] => 40 Minutes Ago 
     [start] => index.js 
     [route] => 127.0.0.1:3000 
     [parameters] => Array 
      (
      ) 
     [machine_id] => E6z5ekvQ 
     [created_by] => 10010 
     [modified_by] => 10010 
     [created] => 2011-09-22T16:30:11-07:00 
     [modified] => 2011-09-22T16:30:11-07:00 
    ) 

注意,该齿轮被合并到对象的一个​​属性,显然齿轮不会出现两次。想法?

+0

循环并匹配唯一的和/或识别的特征,并存储在另一个对象中? –

+2

你可能想考虑为你的对象创建一个类,在那里你可以传递一个数组/对象给构造函数或者一个'load()'方法来设置属性。 –

回答

3

如果你可以通过gear索引数组或索引一些独特的值,它会容易得多。

$indexed = array(); 

// create an array using 'gear' as the index 
foreach($arrayValue as $value) { 
    $indexed[$value['gear']] = $value; 
} 

// loop over each object 
foreach($objectArray as $obj) { 
    $value = $indexed[$obj->gear]; // find the corresponding array 
    foreach($value as $name => $val) { 
     $obj->$name = $val; // assign each array index/value pair to the object 
    } 
} 

如果可能让你的代码默认返回带索引的数组,你可以删除第一个foreach循环。

希望有所帮助。