如果你的编译器支持C++ 11,可以使用两种基于范围的嵌套for循环。查看功能void index_table::dump()
。
// Output function
void index_table::dump() {
for (list<entry> &le : table) {
for (entry &e : le) {
e.dump();
}
}
}
我也是在入门级,其输出两个变量,这是现在私人的内容创建功能dump()
。
class index_table {
public:
index_table() {
table.resize(128);
}
void insert (int,string&,int);
void dump();
private:
class entry {
private:
string word;
int value;
public:
entry (string word, int value) {
this->word = word;
this->value = value;
}
void dump() {
cout << "Word/value is: " << word << "/" << value << endl;
}
};
vector< list <entry> > table;
};
void index_table::insert(int c, string &key, int value) {
//void index_table::insert(string &key, int value) {
entry obj(key, value);
table[c].push_back(obj);
}
// Output function
void index_table::dump() {
for (list<entry> &le : table) {
for (entry &e : le) {
e.dump();
}
}
}
int main (int argc, char **argv) {
index_table mytable;
string a = "String 0-A";
string b = "String 0-B";
string c = "String 1-A";
string d = "String 1-B";
string e = "String 6-A";
string f = "String 6-B";
mytable.insert(0, a, 1);
mytable.insert(0, b, 2);
mytable.insert(1, c, 3);
mytable.insert(1, d, 4);
mytable.insert(6, e, 3);
mytable.insert(6, f, 4);
mytable.dump();
}
计划的成果:
Word/value is: String 0-A/1
Word/value is: String 0-B/2
Word/value is: String 1-A/3
Word/value is: String 1-B/4
Word/value is: String 6-A/3
Word/value is: String 6-B/4
PS:我也改变了你的代码位,使之成为我的测试运行更加容易。