2017-02-13 26 views
3

根据组变量,我试图使用by函数来替换数据帧中多个变量的异常值。 以下是我的努力。但是,我收到一个错误。替换每个组的异常值

# R code: 
library(tidyverse) 
library(dplyr) 
# outlier function definition 
my_outlier <- function(x){ 
stats <- boxplot.stats(unlist(x)) 
outlier <- stats$out 
outlier_idx <- which(unlist(x) %in% outlier) 
max <- max(x[-outlier_idx]); min <- min(x[-outlier_idx]) 
x <- ifelse(x>max, max,ifelse(x < min, min, x)) 
return(x) 
} 
# use the above defined func to substitue outliers of 1 variable in a dataframe, according to a Group variable. 
group_data <- as_tibble(data.frame(x=c(runif(10),2.5,-2.3,runif(10,1,2),3.5,-1.5), group=c(rep(1,12),rep(2,12)))) 

View(group_data) 
by(group_data$x, group_data$group, my_outlier, simplify=FALSE) 
# use the above defined func to substitue outliers of 1+ variable in a dataframe, according to a Group variable.  
group_datas <- as_tibble(data.frame(x=c(runif(10),2.5,-2.3,runif(10,1,2),3.5,-1.5), 
           y=c(runif(10,2,3),4,-1,runif(10,3,4),6,-1), 
           group=c(rep(1,12),rep(2,12)))) 
by(group_data[,1:2], group_data$group, my_outlier) 

当使用我定义的函数根据组变量取代数据框中1+变量的异常值时,出现错误。

我不知道我的代码的哪一部分导致了错误。

+0

你缺少列索引,你要计算的列max'中的最大值 - (max [-outlier_idx]); min < - min(x [-outlier_idx])'。如果你想考虑整个矩阵,包括组列,你需要在'outlier_idx'后添加逗号作为'max < - max(x [-outlier_idx,]); min < - min(x [-outlier_idx,])'。还要注意'ifelse'只返回标量而不是向量。 – discipulus

回答

1

对于多元离群,boxplot.stats将无法​​正常工作,您可以使用outlier测试从包outliers

library(outliers) 
my_outlier2 <- function(x, plot=TRUE){ 
    x <- as.matrix(x) 
    outlier <- rbind(outlier(x),outlier(x,opposite=TRUE)) 
    outlier_idx <- which(duplicated(rbind(x, outlier), fromLast=TRUE))#which(apply(mapply(x, outlier, FUN="=="), MARGIN=1, FUN=all)) 
    if (plot) { # if 2-D data, visualize 
    plot(x[,1], x[,2], pch=19, xlab='x', ylab='y') 
    points(x[outlier_idx,1], x[outlier_idx,2], col='red', pch=8, cex=2) 
    legend('topleft', legend=c('non-outlier', 'outlier'), pch=c(19, 8), col=c('black', 'red')) 
    } 
    x <- x[-outlier_idx,] 
    return(x) 
} 

# use the above defined func to substitue outliers of 1+ variable in a dataframe, according to a Group variable.  
group_datas <- as_tibble(data.frame(x=c(runif(10),2.5,-2.3,runif(10,1,2),3.5,-1.5), 
            y=c(runif(10,2,3),4,-1,runif(10,3,4),6,-1), 
            group=c(rep(1,12),rep(2,12)))) 
by(group_datas[,1:2], group_datas$group, my_outlier2) 

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