我知道这是另一个类似主题的主题,但我搜索了stackoverflow,并且找不到我的问题的答案。 情况如下: 我有一个web服务让我们用很多方法调用它testservice。最近我不得不添加一个又一个,所以我所做的:Java Stub类型中的方法不适用于参数
public int addPayments_p24(String sessionId, int pos_id, String amount, String currency, String title, String client, String address, String postal, String city, String country, String email, String language, String p24_sign) throws Exception {
int last_inserted_id=0;
try {
PreparedStatement statement = null;
int timestamp = (int)(System.currentTimeMillis()/1000L);
statement = connection
.prepareStatement(
"Insert into p24_strefa(pos_id,session_id,amount,currency,title,client,address,postal,city,country,email,language,p24_sign,timestamp)" +
"values(?,?,?,?,?,?,?,?,?,?,?,?,?,?);", statement.RETURN_GENERATED_KEYS);
statement.setInt(1, pos_id);
statement.setString(2, sessionId);
statement.setString(3, amount);
statement.setString(4, currency);
statement.setString(5, title);
statement.setString(6, client);
statement.setString(7, address);
statement.setString(8, postal);
statement.setString(9, city);
statement.setString(10, country);
statement.setString(11, email);
statement.setString(12, language);
statement.setString(13, p24_sign);
statement.setInt(14, timestamp);
statement.executeUpdate();
ResultSet rs = statement.getGeneratedKeys();
if(rs.next())
{
last_inserted_id = rs.getInt(1);
}
} catch (Exception ex) {
_log.error("addpayments_p24", ex);
throw ex;
}
finally {
dispose();
}
return last_inserted_id;
}
然后我试图调用从JSP文件中这个方法是这样的:
String sessionId = request.getParameter("p24_session_id");
String amount = request.getParameter("p24_amount");
String currencys = request.getParameter("p24_currency");
String title = request.getParameter("p24_description");
String client = request.getParameter("p24_client");
String address = request.getParameter("p24_address");
String postal = request.getParameter("p24_zip");
String city = request.getParameter("p24_city");
String country = request.getParameter("p24_country");
String email = request.getParameter("p24_email");
String language = request.getParameter("p24_language");
String sign = get_sign_str(sessionId,amount,currencys);
int pos_id = 2414;
int testResponse;
try {
if (test== null) {
inittest();
}
testResponse = test.addPayments_p24("test",2,"test","test","test","test","test","test","test","test","test","test","test");
}
catch (testWebServicesExceptionException e)
{
e.printStackTrace();
}
到web服务的连接是通过这个函数来完成:
private static testWebServicesStub test;
private synchronized void inittest() throws AxisFault {
if (test == null) {
String testWebServicesEndpoint = Settings
.gettestWebServicesEndpoint();
test= new testWebServicesStub(testWebServicesEndpoint);
}
}
正如你所看到的我使用Axis2。 而且ofcourse我得到了错误:
The method addPayments_p24(AddPayments_p24) in the type TestWebServicesStub is not applicable for the arguments (String, int, String, String, String, String, String, String, String, String, String, String, String)
我在这个问题第三天现在坐在我实在不明白它。如果任何人有任何想法发生了什么...
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你可以发布'addPayments_p24'的服务器端代码吗?您为Web服务客户端使用什么框架?你可以在调用Web服务之前发布代码。 – Simon
是否有可能由于webservice函数体中的错误而返回该错误? – Tomaszeek
要测试问题出在服务器还是客户端上,您可以使用某个REST客户端并直接向Web服务发出请求,以找出问题的出处。您可以使用邮递员(Chrome)或海报(Firefox)等浏览器插件或独立客户端,如SoapUI – Simon