我有两个表backup_policy
和backup_settings
。 backup_policy
有一个名为backup_settings_id
的外键字段,映射到backup_settings
id
字段。这是执行以创建两个表Symfony3外键关系实体不工作
ALTER TABLE `backup_policy_scheduler`
ADD FOREIGN KEY (`backup_policy_id`) REFERENCES `backup_policy` (`id`)
现在的问题是,当我尝试这个代码,屏幕上不断加载,给我最大的执行误差之间的关系查询。
$repository=$this->getDoctrine()>getRepository('AppBundle:BackupPolicy');
$settings = $repository->findAll();
当我准备一个sql语句,并执行fetchAll()它获取结果。
当我尝试插入记录它给了我下面的错误:
Type error: Argument 1 passed to AppBundle\Entity\BackupPolicy::setBackupSettings() must be an instance of AppBundle\Entity\BackupSettings, string given, called in /var/www/symfonyproject/src/AppBundle/Controller/BackupPolicyController.php on line 46
<?php
namespace AppBundle\Entity;
use Doctrine\ORM\Mapping as ORM;
/**
* BackupPolicy
*
* @ORM\Table(name="backup_policy")
*@ORM\Entity(repositoryClass="AppBundle\Entity\Repository\BackupPolicyRepository")
*/
class BackupPolicy
{
/**
* @var integer
*
* @ORM\Column(name="id", type="integer", nullable=false)
* @ORM\Id
* @ORM\GeneratedValue(strategy="IDENTITY")
*/
private $id;
/**
* @var \BackupSettings
*
* @ORM\ManyToOne(targetEntity="BackupSettings")
* @ORM\JoinColumns({
* @ORM\JoinColumn(name="backup_settings_id", referencedColumnName="id")
* })
*/
private $backupSettings;
/**
* Get id
*
* @return integer
*/
public function getId()
{
return $this->id;
}
/**
* Set backupSettings
*
* @param \AppBundle\Entity\BackupSettings $backupSettings
*
* @return BackupPolicy
*/
public function setBackupSettings(\AppBundle\Entity\BackupSettings $backupSettings = null)
{
$this->backupSettings = $backupSettings;
return $this;
}
/**
* Get backupSettings
*
* @return \AppBundle\Entity\BackupSettings
*/
public function getBackupSettings()
{
return $this->backupSettings;
}
}
你的错误是,你尝试分配$这个 - > backupSettings一个字符串。在你的控制器行46中。这与foreignn密钥或映射无关。 显示您的控制器。 – Alsatian
是的,我说得对。我只插入一个字符串。当我插入backup_settings表时,我得到了这个。但为什么即使findAll()不工作? –
请显示控制器。 – Alsatian