将XAML转换为c＃

Question

我需要将followinf代码转换为c＃代码。 有一种工具可以自动执行它？ 谢谢

<ListView Name="listView" Margin="0,0,0,164"> 
     <ListView.View> 
      <GridView> 
       <GridView.Columns> 
        <GridViewColumn Header="Devise" DisplayMemberBinding="{Binding Path=devise}" Width="80" /> 
        <GridViewColumn Header="Libelle" DisplayMemberBinding="{Binding Path=label}" Width="120" /> 
        <GridViewColumn Header="Unite" DisplayMemberBinding="{Binding Path=unite}" Width="80" /> 
        <GridViewColumn Header="Achat" DisplayMemberBinding="{Binding Path=achatBanque}" Width="80" /> 
        <GridViewColumn Header="Vente" DisplayMemberBinding="{Binding Path=venteBanque}" Width="80" />  
       </GridView.Columns> 
      </GridView> 
     </ListView.View> 
    </ListView> 

Answer 1

没有没有自动做到这一点的工具，但一般而言，您可以采取的属性，并将其更改为设置属性。尽管您可能会失去某些类型的自动转换功能，但在这种情况下，您只需确定属性的类型并使用它（如下面的边距）即可。

例如：

var gridView = new GridView(); 

gridView.Columns.Add(new GridViewColumn() { 
    Header = "Devise", 
    DisplayMemberBinding = new Binding() { Path = "devise" }, 
    Width = 80 
}); 
// ... 

var listView = new ListView() { 
    Name = "listView", 
    Margin = new Thickness(0, 0, 0, 164), 
    View = gridView 
}; 

Answer 2

我认为这样做不应该是硬（使用的CodeDOM），所以我就开始寻找解决方案的工作。来源可用at github。这只是一个开始，它不支持许多XAML的功能，但它适用于问题中的代码。

如果您认真对待此问题，可以进一步研究该代码。

在问题中的XAML产生下面的输出，这似乎工作：

private ListView Get() 
{ 
    ListView listView = new ListView(); 
    listView.Name = "listView"; 
    listView.Margin = ((Thickness)(TypeDescriptor.GetConverter(typeof(Thickness)).ConvertFromInvariantString("0,0,0,164"))); 
    GridView gridView = new GridView(); 
    GridViewColumn gridViewColumn = new GridViewColumn(); 
    gridViewColumn.Header = "Devise"; 
    Binding binding = new Binding(); 
    binding.Path = ((PropertyPath)(TypeDescriptor.GetConverter(typeof(PropertyPath)).ConvertFromInvariantString("devise"))); 
    gridViewColumn.DisplayMemberBinding = binding; 
    gridViewColumn.Width = 80D; 
    gridView.Columns.Add(gridViewColumn); 
    GridViewColumn gridViewColumn2 = new GridViewColumn(); 
    gridViewColumn2.Header = "Libelle"; 
    Binding binding2 = new Binding(); 
    binding2.Path = ((PropertyPath)(TypeDescriptor.GetConverter(typeof(PropertyPath)).ConvertFromInvariantString("label"))); 
    gridViewColumn2.DisplayMemberBinding = binding2; 
    gridViewColumn2.Width = 120D; 
    gridView.Columns.Add(gridViewColumn2); 
    GridViewColumn gridViewColumn3 = new GridViewColumn(); 
    gridViewColumn3.Header = "Unite"; 
    Binding binding3 = new Binding(); 
    binding3.Path = ((PropertyPath)(TypeDescriptor.GetConverter(typeof(PropertyPath)).ConvertFromInvariantString("unite"))); 
    gridViewColumn3.DisplayMemberBinding = binding3; 
    gridViewColumn3.Width = 80D; 
    gridView.Columns.Add(gridViewColumn3); 
    GridViewColumn gridViewColumn4 = new GridViewColumn(); 
    gridViewColumn4.Header = "Achat"; 
    Binding binding4 = new Binding(); 
    binding4.Path = ((PropertyPath)(TypeDescriptor.GetConverter(typeof(PropertyPath)).ConvertFromInvariantString("achatBanque"))); 
    gridViewColumn4.DisplayMemberBinding = binding4; 
    gridViewColumn4.Width = 80D; 
    gridView.Columns.Add(gridViewColumn4); 
    GridViewColumn gridViewColumn5 = new GridViewColumn(); 
    gridViewColumn5.Header = "Vente"; 
    Binding binding5 = new Binding(); 
    binding5.Path = ((PropertyPath)(TypeDescriptor.GetConverter(typeof(PropertyPath)).ConvertFromInvariantString("venteBanque"))); 
    gridViewColumn5.DisplayMemberBinding = binding5; 
    gridViewColumn5.Width = 80D; 
    gridView.Columns.Add(gridViewColumn5); 
    listView.View = gridView; 
    return listView; 
}