正则表达式来获得<a href> from a string in java

Question

Suppose I have

<img class="size-full wp-image-10225" alt="animals" src="abc.jpg"> blah blah blah&nbsp; 
<a href="http://en.wikipedia.org/wiki/Elephant">elephant is an animal</a>&nbsp;blah 

I want a regex to give me the output :

blah blah blah <a href="http://en.wikipedia.org/wiki/Elephant">elephant is an animal</a> blah 

without the  . I can do str.replace(" ","") separately, but how do I get the string starting from blah blah... until blah (which includes link tag).

Answer 1

Maybe something like this?

^<[^>]*>\s*|&nbsp; 

Java escaped:

^<[^>]*>\\s*|&nbsp; 

regex101 demo

^<[^>]*>\\s*将第一img标签以及任何后续的空间相匹配。然后替换 。替换字符串是""。

虽然您可能想要使用适当的HTML解析器，因为它不太可能中断。