2014-10-28 79 views
0

我正在为Java构建游戏,并且已经归结为最后部分之一。还有其他需要解决的问题,这些问题很容易解决。虽然我无法弄清楚一个问题,那就是每次运行游戏后我都无法得到新的随机数字。在Java中猜测游戏获取新的随机数

例如,如果没有人猜测数字(1-20)随机产生的数字比游戏重复的数字。在此期间你正在玩2台电脑,并且它们的数字也是随机组成的(再有1-20个值)。

下面是一些在Player类的代码中我做了

import java.util.Scanner; 
import java.util.Random; 

public class Player { 
    private double currentGuess = 0; 
    private String firstName; 
    private boolean isCorrect; 
    Scanner myScanner = new Scanner(System.in); 

public Player() { 
} 

public double autoGuess() { 
    Random randomNumber = new Random(); 
    double number = randomNumber.nextInt(20) + 1; 

    return number; 
} 

这里是我GuessGame类,这是那里的行动实际发生。我无法弄清楚为什么当我打电话给autoGuess方法(从玩家类)时,我无法在每场比赛后得到新的随机数字,导致没有人猜测正确的数字。随机生成要猜测的数字(WINNING_NUMBER)也是如此,每次新游戏后仍然保持不变。以下是我的GuessGame类的一些代码。

import java.util.Random; 

public class GuessGame { 
    Player player1 = new Player(); 
    Player player2 = new Player(); 
    Player player3 = new Player(); 

    double player2Guess = player2.autoGuess(); 
    double player3Guess = player3.autoGuess(); 
    int numberOfTries = 0; 

public double generateWinningNumber() { 
    Random randomGenerate = new Random(); 
    double randomNumber = randomGenerate.nextInt(20) + 1; 

    return randomNumber; 
} 

private final double WINNING_NUMBER = generateWinningNumber(); 

public void startGame() { 
    System.out.println("VM: Welcome we are going to play a number guessing game. I'm (the JVM)\n" 
      + "going to randomly pick a number between 0 and 20. You and the 2 other\n" 
      + "computer-generated players are going to try to guess that number. The game\n" 
      + "will end when at least one of the players correctly guesses the number.\n"); 

    System.out.println(WINNING_NUMBER); 

    System.out.print("What is your name? "); 
     String player1Name = player1.readName(); 

    while (player1.isCorrect() == false)  
     { 

     System.out.print(player1Name + ", enter your guess: "); 
      player1.readGuess(); 
      player2.autoGuess(); 
      player3.autoGuess(); 

      numberOfTries++; 

      if (player1.getCurrentGuess() == WINNING_NUMBER || player2Guess == WINNING_NUMBER || player3Guess == WINNING_NUMBER) 
      { 
       player1.setCorrect(true); 
       displayGuesses(); 
       determineWinner(); 
      } 

      else 
      { 
       displayGuesses(); 
       displayHints(); 
       System.out.println("No one guessed the number.\nPlayers will need to guess again.\n"); 
       System.out.println("The winning number was: " + WINNING_NUMBER); 
       generateWinningNumber(); 
      } 
     } 
} 


public void displayGuesses() { 
    System.out.print("Player 2's guess is: " + player2Guess + "\n"); 
    System.out.print("Player 3's guess is: " + player3Guess + "\n\n"); 
} 

还有更多的问题需要解决,但我试图解决这个问题。我有我的驾驶员课程开始这个游戏,也知道我需要将我的号码四舍五入到Ints,所以没有小数位。而且,所有提示方法都指的是,如果陈述告诉你,如果你是热的,温暖的或冷的。这运行得很好。只需要一些帮助,在我的while语句每次新的不成功的游戏之后,弄清楚如何获得一个新的随机数。

回答

0

你的generateWinningNumber()方法返回一个double,它实际上并没有改变任何值本身。另外,因为WINNING_NUMBER是一个常量,即使您确实想要更改它,您也无法完成这项工作。你绝对不应该使WINNING_NUMBER最终,并修改generateWinningNumber(),以便它本身修改你的全局变量,或保持原样,并使用它的返回值分配给你的非常量winningNumber全局。

+2

...并在循环外部创建Random()对象。 – 2014-10-28 19:40:35

+1

要添加到Mike说的话,您的autoGuess()也会返回一个double值,并且不会更改任何值。而不是以double形式返回变量号,函数应该将currentGuess设置为变量号并返回void。 – user1521640 2014-10-28 19:43:15

+0

@LeeDanielCrocker不是已经有了吗?随机对象是在不同的方法中创建的,所以它们不会被重用。 – 2014-10-28 19:43:39