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下面是我拥有的一个简单示例。如果我有两个任务step1和step2,并且step1是一个依赖项,我如何读取步骤2中step1的返回值(从输出)?保存来自python-Luigi的返回值
class step1(luigi.Task):
shardNum = luigi.Parameter()
def run(self):
with open('workfile1', 'w') as f:
f.write("TEST")
def output(self):
return [luigi.LocalTarget("workfile1")]
#HOW DO I READ THE RETURN VALUE OF THIS IN STEP2?
class step2(luigi.Task):
def requires(self):
#HOW CAN I GET THE TARGET; luigi.LocalTarget("workfile1"); AND USE IT ELSEHOW?
return step1()
def run(self):
with open('workfile2', 'w') as f:
f.write("TEST")
def output(self):
return luigi.LocalTarget("workfile2")
编辑:这似乎是的hackish,但工作(有没有更好/更清洁的方式?)
class step2(luigi.Task):
...
def run(self):
print(self.requires().output()[0])#prints the output from last function
with open('workfile2', 'w') as f:
f.write("TEST")
...